The current through a 220 μF capacitor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 1.5sin(2500t + 30°) mA and i2 = 4.7sin(200t – 40°) mA
The current through a 220 μF capacitor is given below. Use Ohm’s Law to find the voltage. Convert to polar form, find the impedance and complete the math, then convert back to the waveform at i1 = 1.5sin(2500t + 30°) mA and i2 = 4.7sin(200t – 40°) mA
Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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The current through a 220 μF capacitor is given below. Use Ohm’s Law to find the voltage.
Convert to polar form, find the impedance and complete the math, then convert back to the
waveform at i1 = 1.5sin(2500t + 30°) mA and i2 = 4.7sin(200t – 40°) mA
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