var numbers 00 function changeNums (numList, addNum GubtractNum) ( for (var 10: 1< numList.length ; 0) ( if( numList i 3 -- 0)( numList i numList 0 + addNum else ( numList fi numList i subtractNum WO 3, 2: changeNums (numbers console.log (numbers); A. [2, 5, 3, 1, 6] B. [0, 3, 6, -1, 9] С. [-1, 2, 6, -2, 8] D. [5, 2, 6, 3, 9]

Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
3.
What will be printed to the console after this program runs?
var numbers = [2, 5, 3, 1, 6]
%3D
function changeNums (numList, addNum, subtractNum){
for(var i=0; i<numList.length; i++){
if(numList[i] % 3 == 0){
numList[i] = numList[i] + addNum;
} else {
numList[i] = numList[i] - subtractNum;
}
}
}
changeNums (numbers, 3, 2);
console.log(numbers);
Transcribed Image Text:3. What will be printed to the console after this program runs? var numbers = [2, 5, 3, 1, 6] %3D function changeNums (numList, addNum, subtractNum){ for(var i=0; i<numList.length; i++){ if(numList[i] % 3 == 0){ numList[i] = numList[i] + addNum; } else { numList[i] = numList[i] - subtractNum; } } } changeNums (numbers, 3, 2); console.log(numbers);
var numbers -
2 6 3
addNum
subtractNum) {--
function changeNums (numList
for( var 1 0: 1< numList.length : 0)
if(
numList i
3)
numList i
numList i
+ addNum
) else (
numList 0
numList a
subtractNum
3. 2:
changeNums (numbers
console.log (numbers):
A. [2, 5, 3, 1, 6]
В.
[о, 3, 6, -1, 9]
C. [-1, 2, 6, -2, 8]
С.
D. [5, 2, 6, 3, 9]
Transcribed Image Text:var numbers - 2 6 3 addNum subtractNum) {-- function changeNums (numList for( var 1 0: 1< numList.length : 0) if( numList i 3) numList i numList i + addNum ) else ( numList 0 numList a subtractNum 3. 2: changeNums (numbers console.log (numbers): A. [2, 5, 3, 1, 6] В. [о, 3, 6, -1, 9] C. [-1, 2, 6, -2, 8] С. D. [5, 2, 6, 3, 9]
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