1 import math 2- #Function I: def func1(n): count 0 sum = 0 3&567∞9 4 8 979982~~~~~~~ 9 10 11- #Function II: 12 - def func2(n): 13 14 15 16 17 18 19 21 22 23 24 20 #Function III: def func3(n): count 0 sum = 0 for i in range(int(math.pow(1.02,n))): sum += i 25 26 for i in range(int(math.log2(n))): sum += i count += 1 print("for n {}: count 31 32 33 count 0 sum = 0 for i in range(int(n*n)): sum += i count += 1 print("for n = {}: count n = [2,10,100,1000, 10000] 30 for i in n: func1(i) func2(i) func3(i) count += 1 print("for n {}: count {}".format(n, count)) {}".format(n, count)) {}".format(n, count))
1 import math 2- #Function I: def func1(n): count 0 sum = 0 3&567∞9 4 8 979982~~~~~~~ 9 10 11- #Function II: 12 - def func2(n): 13 14 15 16 17 18 19 21 22 23 24 20 #Function III: def func3(n): count 0 sum = 0 for i in range(int(math.pow(1.02,n))): sum += i 25 26 for i in range(int(math.log2(n))): sum += i count += 1 print("for n {}: count 31 32 33 count 0 sum = 0 for i in range(int(n*n)): sum += i count += 1 print("for n = {}: count n = [2,10,100,1000, 10000] 30 for i in n: func1(i) func2(i) func3(i) count += 1 print("for n {}: count {}".format(n, count)) {}".format(n, count)) {}".format(n, count))
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
. Initialize please.
![1 import math
2 #Function I:
3 def func1(n):
4
count
sum 0
for i in range(int(math.log2(n))):
sum += i
count += 1
print("for n = {}: count = {}".format(n, count))
68 69 SA ENT
5
6-
7
9
10
0
11- #Function II:
12 def func2(n):
13
count
14
sum = 0
15
for i in range(int(n*n)):
16
sum += i
17
18
19
20
#Function III:
21 def func3(n):
22
23
24
25
26
27
28
29
30
31
32
33
count += 1
print("for n = {}: count = {}".format(n, count))
count
sum = 0
for i in range(int(math.pow(1.02,n))):
sum +=
count += 1
print("for n = {}: count = {}".format(n, count))
0
n =
for i in n:
func1(i)
func2(i)
func3(i
[2,10,100,1000, 10000]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fef78d13c-2e10-4bd8-9c35-da08f85fbe6e%2Ffa239230-0e66-45ba-8e77-2872779aa66d%2F4zzliu_processed.png&w=3840&q=75)
Transcribed Image Text:1 import math
2 #Function I:
3 def func1(n):
4
count
sum 0
for i in range(int(math.log2(n))):
sum += i
count += 1
print("for n = {}: count = {}".format(n, count))
68 69 SA ENT
5
6-
7
9
10
0
11- #Function II:
12 def func2(n):
13
count
14
sum = 0
15
for i in range(int(n*n)):
16
sum += i
17
18
19
20
#Function III:
21 def func3(n):
22
23
24
25
26
27
28
29
30
31
32
33
count += 1
print("for n = {}: count = {}".format(n, count))
count
sum = 0
for i in range(int(math.pow(1.02,n))):
sum +=
count += 1
print("for n = {}: count = {}".format(n, count))
0
n =
for i in n:
func1(i)
func2(i)
func3(i
[2,10,100,1000, 10000]
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