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Using the given standard enthalpies of formation in the table to calculate A Horxn for this reaction. 2 CH3OH(1) + O2(g) → CH3COOH(I) + 2 H2O(1) AHof CH3OH(1) -238 kJ/mol CH3COOH(1) -487 kJ/mol H2O(1) -286 kJ/mol H₂O(g) -241 kJ/mol

Using the given standard enthalpies of formation in the table to calculate A Horxn for this reaction. 2 CH3OH(1) + O2(g) → CH3COOH(I) + 2 H2O(1) AHof CH3OH(1) -238 kJ/mol CH3COOH(1) -487 kJ/mol H2O(1) -286 kJ/mol H₂O(g) -241 kJ/mol

Chemistry: The Molecular Science
Chemistry: The Molecular Science
5th Edition
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:John W. Moore, Conrad L. Stanitski
Chapter4: Energy And Chemical Reactions
Section4.7: Where Does The Energy Come From?
Problem 4.13CE
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i know the answer is -583kJ but I did not understand why. I would appreciate any help on how to solve this step by step, thank you :) 

Using the given standard enthalpies of formation in the table to calculate A Horxn for this reaction. 2 CH3OH(1) + O2(g) → CH3COOH(I) + 2 H2O(1) AHof CH3OH(1) -238 kJ/mol CH3COOH(1) -487 kJ/mol H2O(1) -286 kJ/mol H₂O(g) -241 kJ/mol
Transcribed Image Text:Using the given standard enthalpies of formation in the table to calculate A Horxn for this reaction. 2 CH3OH(1) + O2(g) → CH3COOH(I) + 2 H2O(1) AHof CH3OH(1) -238 kJ/mol CH3COOH(1) -487 kJ/mol H2O(1) -286 kJ/mol H₂O(g) -241 kJ/mol
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