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16.36 For the reaction 2A +B→C+D+ 2E, data for a run with [A]o 800 mmol/L and [B]₁ = 2.00 mmol/L are t/ks 8 14 20 30 50 90 [B]/[B], 0.836 0.745 0.680 0.582 0.452 0.318 600 mmol/L and [B] = and data for a run with [A]o 2.00 mmol/L are t/ks [B]/[B]o Find the rate law and rate constant. 8 0.901 = 20 0.787 50 0.593 90 0.453

16.36 For the reaction 2A +B→C+D+ 2E, data for a run with [A]o 800 mmol/L and [B]₁ = 2.00 mmol/L are t/ks 8 14 20 30 50 90 [B]/[B], 0.836 0.745 0.680 0.582 0.452 0.318 600 mmol/L and [B] = and data for a run with [A]o 2.00 mmol/L are t/ks [B]/[B]o Find the rate law and rate constant. 8 0.901 = 20 0.787 50 0.593 90 0.453

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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16.36 For the reaction 2A + B → C + D + 2E, data for a run with [A]o = 800 mmol/L and [B]₁ = 2.00 mmol/L are t/ks 8 14 20 30 50 90 [B]/[B] 0.836 0.745 0.680 0.582 0.452 0.318 600 mmol/L and [B] and data for a run with [A]o 2.00 mmol/L are t/ks 20 [B]/[B]o 0.787 Find the rate law and rate constant. 8 0.901 = 50 0.593 90 0.453 =
Transcribed Image Text:16.36 For the reaction 2A + B → C + D + 2E, data for a run with [A]o = 800 mmol/L and [B]₁ = 2.00 mmol/L are t/ks 8 14 20 30 50 90 [B]/[B] 0.836 0.745 0.680 0.582 0.452 0.318 600 mmol/L and [B] and data for a run with [A]o 2.00 mmol/L are t/ks 20 [B]/[B]o 0.787 Find the rate law and rate constant. 8 0.901 = 50 0.593 90 0.453 =
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