Using the curved arrow formalism, draw out the mechanism for each reaction shown below. Be sure to show the flow of all electrons, using multiple arrows when necessary. Hint: if you get stuck, try drawing in any missing lone pairs! A H3N: + H-Br: H3N-H + : Br: CI -OH -BH, вн, + CH, —О— CH, → CH,-O –CH, О..
Reactive Intermediates
In chemistry, reactive intermediates are termed as short-lived, highly reactive atoms with high energy. They rapidly transform into stable particles during a chemical reaction. In specific cases, by means of matrix isolation and at low-temperature reactive intermediates can be isolated.
Hydride Shift
A hydride shift is a rearrangement of a hydrogen atom in a carbocation that occurs to make the molecule more stable. In organic chemistry, rearrangement of the carbocation is very easily seen. This rearrangement can be because of the movement of a carbocation to attain stability in the compound. Such structural reorganization movement is called a shift within molecules. After the shifting of carbocation over the different carbon then they form structural isomers of the previous existing molecule.
Vinylic Carbocation
A carbocation where the positive charge is on the alkene carbon is known as the vinyl carbocation or vinyl cation. The empirical formula for vinyl cation is C2H3+. In the vinyl carbocation, the positive charge is on the carbon atom with the double bond therefore it is sp hybridized. It is known to be a part of various reactions, for example, electrophilic addition of alkynes and solvolysis as well. It plays the role of a reactive intermediate in these reactions.
Cycloheptatrienyl Cation
It is an aromatic carbocation having a general formula, [C7 H7]+. It is also known as the aromatic tropylium ion. Its name is derived from the molecule tropine, which is a seven membered carbon atom ring. Cycloheptatriene or tropylidene was first synthesized from tropine.
Stability of Vinyl Carbocation
Carbocations are positively charged carbon atoms. It is also known as a carbonium ion.
![Using the curved arrow formalism, draw
out the mechanism for each reaction shown
below. Be sure to show the flow of all
electrons, using multiple arrows when
necessary. Hint: if you get stuck, try
drawing in any missing lone pairs!
A
H3N: +
H-Br:
H3N-H + :Br:
B
CI
CI
-OH
H.
-BH,
BH, + CH,-0-CH,
CH,—О — Сн,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2f591c64-216a-4120-ac44-1b23dfa641af%2Fc90e5c6c-b136-4de1-808a-9a900ca81947%2Flt69u09_processed.jpeg&w=3840&q=75)
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In the given reactions the role of lone pair of electrons on the hetero atoms in the organic transformation are clearly indicated.
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