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Use the two templates to draw both enantiomers for the next questions. The isopropyl group and methyl group is provided so you have to fill in the remaining groups, and the hydrogen atom. 1. OsO4 + CH3 2. NaHSO3, H20 CH3 CH3 enantiomeric pair 1. CPBA CH3 2. H*, H2O CH3 CH3 enantiomeric pair

Use the two templates to draw both enantiomers for the next questions. The isopropyl group and methyl group is provided so you have to fill in the remaining groups, and the hydrogen atom. 1. OsO4 + CH3 2. NaHSO3, H20 CH3 CH3 enantiomeric pair 1. CPBA CH3 2. H*, H2O CH3 CH3 enantiomeric pair

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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## Explanation of Stereochemistry Reactions In the following sections, we will explore how to draw both enantiomers for the given chemical reactions. The isopropyl group and methyl group are already provided, and you will need to complete the structures by filling in the remaining groups and the hydrogen atom. ### Reaction 1: Osmium Tetroxide Addition **Reaction Scheme:** - **Reactants:** - An alkene with an isopropyl group and a methyl group attached. - **Reagents:** 1. **OsO₄ (osmium tetroxide)** 2. **NaHSO₃ (sodium bisulfite), H₂O** **Products:** - Two molecules (enantiomeric pair) with an addition of -OH groups. - Each enantiomer has different spatial arrangements of the groups attached to the carbon atoms. **Reaction Explanation:** This process typically leads to the formation of cis-diols through the syn-addition of hydroxyl groups across the double bond. **Enantiomeric Pair:** - Each enantiomer has the -OH groups added across the double bond in syn-fashion but with different stereochemistry on the two carbons where groups are added. ### Reaction 2: mCPBA Epoxidation and Hydrolysis **Reaction Scheme:** - **Reactants:** - Same starting alkene. - **Reagents:** 1. **mCPBA (meta-Chloroperoxybenzoic acid)** 2. **H⁺ (acid), H₂O** **Products:** - Two enantiomers with different spatial arrangements of added groups - Each enantiomer belongs to an enantiomeric pair. **Reaction Explanation:** This reaction involves the formation of an epoxide intermediate via the oxidation of the double bond by mCPBA, followed by hydrolysis to form diols. **Enantiomeric Pair:** - Each enantiomer results from anti-addition of -OH groups. ### Diagram Description - **Top Diagram:** - Shows an alkene reacting with OsO₄ followed by NaHSO₃ and H₂O, resulting in a pair of enantiomers with syn-addition of hydroxyl groups. - **Bottom Diagram:** - Illustrates the same alkene reacting with mCPBA followed by H⁺ and
Transcribed Image Text:## Explanation of Stereochemistry Reactions In the following sections, we will explore how to draw both enantiomers for the given chemical reactions. The isopropyl group and methyl group are already provided, and you will need to complete the structures by filling in the remaining groups and the hydrogen atom. ### Reaction 1: Osmium Tetroxide Addition **Reaction Scheme:** - **Reactants:** - An alkene with an isopropyl group and a methyl group attached. - **Reagents:** 1. **OsO₄ (osmium tetroxide)** 2. **NaHSO₃ (sodium bisulfite), H₂O** **Products:** - Two molecules (enantiomeric pair) with an addition of -OH groups. - Each enantiomer has different spatial arrangements of the groups attached to the carbon atoms. **Reaction Explanation:** This process typically leads to the formation of cis-diols through the syn-addition of hydroxyl groups across the double bond. **Enantiomeric Pair:** - Each enantiomer has the -OH groups added across the double bond in syn-fashion but with different stereochemistry on the two carbons where groups are added. ### Reaction 2: mCPBA Epoxidation and Hydrolysis **Reaction Scheme:** - **Reactants:** - Same starting alkene. - **Reagents:** 1. **mCPBA (meta-Chloroperoxybenzoic acid)** 2. **H⁺ (acid), H₂O** **Products:** - Two enantiomers with different spatial arrangements of added groups - Each enantiomer belongs to an enantiomeric pair. **Reaction Explanation:** This reaction involves the formation of an epoxide intermediate via the oxidation of the double bond by mCPBA, followed by hydrolysis to form diols. **Enantiomeric Pair:** - Each enantiomer results from anti-addition of -OH groups. ### Diagram Description - **Top Diagram:** - Shows an alkene reacting with OsO₄ followed by NaHSO₃ and H₂O, resulting in a pair of enantiomers with syn-addition of hydroxyl groups. - **Bottom Diagram:** - Illustrates the same alkene reacting with mCPBA followed by H⁺ and
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