### Confidence Interval and Point Estimate for Population ProportionUse the sample data and confidence level given below to complete parts (a) through (d).A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, \( n = 948 \) and \( x = 538 \) who said "yes." Use a 90% confidence level.#### Steps to Solve:1. **Click the icon to view a table of z scores.** (A table of z scores is typically provided in statistics textbooks and online resources to help determine the critical value for the confidence interval.)#### a) Find the best point estimate of the population proportion \( p \).\[ \text{Point Estimate} = \frac{x}{n} \]\[ \boxed{} \]*(Round to three decimal places as needed.)*#### b) Identify the value of the margin of error \( E \).\[ E = z \times \sqrt{\frac{p(1 - p)}{n}} \]\[ \text{Where:} \]- \( z \) is the critical value for the 90% confidence level- \( p \) is the sample proportion calculated in part (a)\[ E = \boxed{} \]*(Round to three decimal places as needed.)*#### c) Construct the confidence interval.\[ p - E < p < p + E \]\[ \boxed{} < p < \boxed{} \]*(Round to three decimal places as needed.)*---This page guides you through the calculations necessary to find the best point estimate, margin of error, and confidence interval for the population proportion based on a given sample data set and confidence level. **Interpreting Confidence Intervals****Question:**Write a statement that correctly interprets the confidence interval. Choose the correct answer below.**Options:**A. One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.B. 90% of sample proportions will fall between the lower bound and the upper bound.C. There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound.D. One has 90% confidence that the sample proportion is equal to the population proportion.

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Description: ### Confidence Interval and Point Estimate for Population ProportionUse the sample data and confidence level given below to complete parts (a) through (d).A research institute poll asked respondents if they felt vulnerable to identity theft. In the

It is given that sample size (n) is 948 and x is 538.

Math

Statistics

Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 948 and x = 538 who said "yes." Use a 90% confidence level. E Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.

Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 948 and x = 538 who said "yes." Use a 90% confidence level. E Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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POSITIVE z Scores Standard Normal (2) Distribution: Cumulative Area from the LEFT 00 03 04 00 so0 S120 S160 S1 535 00 01 5478 S517 S57 SS S S714 5753 01 02 5790 103 6141 02 03 8179 8217 255 6331 443 6517 03 04 4700 679 04 0.5 J 7123 7157 7190 7224 0.5 0. 724 7367 744 746 7S17 7549 07 7580 7611 J642 7704 734 764 7852 07 7681 106 8133 08 0.9 8159 8186 212 8264 時 8340 0.9 10 413 577 M21 10 1.1 70 AT729 M10 1.1 07 es 12 44 12 1.3 9032 S115 131 147 9162 177 13 14 14 1.5 3418 3441 1.5 14 s43 474 344 45 16 1.7 9554 564 3 591 17 18 18 1.9 3713 S732 9738 9744 1.9 20 20 21 21 22 22 23 s 01 0 011 23 24 es 24 25 25 26 26 27 071 27 28 28 29 29 30 987 0 3.0 31 31 32 32 33 33 34 34 3.50. nd up 350 and up 00 04 07 08 Standard Normal (2) Distribution: Cumulative Area from the LEFT
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