Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 967 and x = 560 who said "yes." Use a 99% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E=D (Round to three decimal places as needed.) c) Construct the confidence interval. (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. O A. 99% of sample proportions will fall between the lower bound and the upper bound. O B. One has 99% confidence that the sample proportion is equal to the population proportion. OC. One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion. O D. There is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 967 and x = 560 who said "yes." Use a 99% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E=D (Round to three decimal places as needed.) c) Construct the confidence interval. (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below. O A. 99% of sample proportions will fall between the lower bound and the upper bound. O B. One has 99% confidence that the sample proportion is equal to the population proportion. OC. One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion. O D. There is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

Name: POSITIVE z ScoresStandard Normal (2) Distribution: Cumulative Area fr
Uploaded: 2024-03-20T07:07:00.000Z
Channel: Bartleby
Description: POSITIVE z ScoresStandard Normal (2) Distribution: Cumulative Area from the LEFT00030400so0 S120 S160S153500015478 S517 S57 SS SS71457530102579010361410203817982172556331443651703044700679040.5J 71237157719072240.50.72473677447467S1775490775807611J6

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Concept explainers

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.

Topic Video

Question

POSITIVE z Scores
Standard Normal (2) Distribution: Cumulative Area from the LEFT
00
03
04
00
so0 S120 S160
S1
535
00
01
5478 S517 S57 SS S
S714
5753
01
02
5790
103
6141
02
03
8179
8217
255
6331
443
6517
03
04
4700
679
04
0.5
J 7123
7157
7190
7224
0.5
0.
724
7367
744
746
7S17
7549
07
7580
7611
J642
7704
734 764
7852
07
7681
106
8133
08
0.9
8159
8186
212
8264
時
8340
0.9
10
413
577
M21
10
1.1
70 AT729
M10
1.1
07 es
12
44
12
1.3
9032
S115
131
147
9162
177
13
14
14
1.5
3418
3441
1.5
14
s43 474
344
45
16
1.7
9554 564 3
591
17
18
18
1.9
3713
S732
9738
9744
1.9
20
20
21
21
22
22
23
s 01
0 011
23
24
es
24
25
25
26
26
27
071
27
28
28
29
29
30
987
0
3.0
31
31
32
32
33
33
34
34
3.50. nd up
350 and up
00
04
07
08
Standard Normal (2) Distribution: Cumulative Area from the LEFT

Use the sample data and confidence level given below to complete parts (a) through (d).
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 967 and x = 560 who said "yes." Use a 99% confidence level.
E Click the icon to view
table of z scores.
a) Find the best point estimate of the population proportion p.
(Round to three decimal places as needed.)
b) Identify the value of the margin of error E.
E=D
(Round to three decimal places as needed.)
c) Construct the confidence interval.
(Round to three decimal places as needed.)
d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below.
O A. 99% of sample proportions will fall between the lower bound and the upper bound.
O B. One has 99% confidence that the sample proportion is equal to the population proportion.
Oc. One has 99% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion.
O D. There is a 99% chance that the true value of the population proportion will fall between the lower bound and the upper bound.

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POSITIVE z Scores Standard Normal (z) Distribution: Cumulative Area from the LEFT .01 .02 03 04 06 07 08 .5239 5279 .5675 .5319 5160 5557 5949 0.0 5000 5120 5199 5596 5987 6026 6568 6736 yo88. 7422 .7454 ア734 8023 5040 5080 5359 .5517 5753 5438 5832 6217 5714 6105 0.1 .5398 .5478 5636 5793 5910 6064 6141 0.2 0.3 0.4 0.5 5871 ,6406 6772 /123 6293 6331 6443 6480 6517 6255 6628 6179 6844 .7190 .7517 .6808 6879 6700 7019 7o54 7389 6664 6554 6915 6591 .7224 .7549 6950 6985 715% 7357 7486 7257 .7580 7324 ,7642 7291 0.6 0.7 7764 7794 7823 7852 .7673 796/ 8238 .7611 .7/04 7939 8106 8133 7910 8186 0.8 7881 .8365 8599 8389 8315 as54 .a57, 8770 .8340 8264 8508 8/29 8289 .8531 8/49 0.9 .8159 8212 8413 8438 8485 .8621 1.0 8461 8830 .8810 8997 11 8643 8665 8686 8708 8925 a962 4980 9015 8907 9066 .9082 9236 9370 8869 1.2 1.3 9131 9162 9177 9099 9251 9032 .9319 9441 .9279 9292 9306 14 1.5 9207 9345 9222 9357 9265 9394 9332 9382 19406 9418, Print Done in
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For the standard normal distribution shown on the right, find the probability of z occurring in the indicated region. Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table. -0.21 .... The probability is- (Round to four decimal places as needed.) Enter your answer in the answer box and then click Check Answer. Get More Help - Clear All Check Answer HIS SC
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search Determine the area under the standard normal curve that lies to the right of (a) Z=1.09, (b) Z=-1.29, (c) Z= -0.11, and (d) Z=-0.01. Click here to view the standard normal distribution table (page 1). Click here to view the standard normal distribution table (page 2). (a) The area to the right of Z=1.09 is (Round to four decimal places as needed.) (b) The area to the right of Z=-1.29 is (Round to four decimal places as needed.) (c) The area to the right of Z= -0.11 is (Round to four decimal places as needed.) (d) The area to the right of Z= -0.01 is (Round to four decimal places as needed.). At O
Positive z Scores Standard Normal (z) Distribution: Cumulative Area from the Left z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 z 0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 0.0 0.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.1 0.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 0.2 0.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.3 0.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.4 0.5 .6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224 0.5 0.6 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 0.6 0.7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852 0.7 0.8 .7881 .7910 .7939 .7967 .7995 .8023 .8051 .8078 .8106 .8133 0.8 0.9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 0.9 1.0 .8413 .8438 .8461 .8485 .8508 .8531 .8554 .8577 .8599 .8621 1.0 1.1 .8643 .8665 .8686 .8708 .8729 .8749 .8770 .8790 .8810 .8830 1.1 1.2 .8849 .8869 .8888 .8907 .8925 .8944 .8962 .8980 .8997…
Positive z Scores Standard Normal (z) Distribution: Cumulative Area from the Left z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 z0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 0.00.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.10.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 0.20.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.30.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.40.5 .6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224 0.50.6 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 0.60.7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852 0.70.8 .7881 .7910 .7939 .7967 .7995 .8023 .8051 .8078 .8106 .8133 0.80.9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 0.91.0 .8413 .8438 .8461 .8485 .8508 .8531 .8554 .8577 .8599 .8621 1.01.1 .8643 .8665 .8686 .8708 .8729 .8749 .8770 .8790 .8810 .8830 1.11.2 .8849 .8869 .8888 .8907 .8925 .8944 .8962 .8980 .8997 .9015 1.21.3…
Positive z Scores Standard Normal (z) Distribution: Cumulative Area from the Left z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 z0.0 .5000 .5040 .5080 .5120 .5160 .5199 .5239 .5279 .5319 .5359 0.00.1 .5398 .5438 .5478 .5517 .5557 .5596 .5636 .5675 .5714 .5753 0.10.2 .5793 .5832 .5871 .5910 .5948 .5987 .6026 .6064 .6103 .6141 0.20.3 .6179 .6217 .6255 .6293 .6331 .6368 .6406 .6443 .6480 .6517 0.30.4 .6554 .6591 .6628 .6664 .6700 .6736 .6772 .6808 .6844 .6879 0.40.5 .6915 .6950 .6985 .7019 .7054 .7088 .7123 .7157 .7190 .7224 0.50.6 .7257 .7291 .7324 .7357 .7389 .7422 .7454 .7486 .7517 .7549 0.60.7 .7580 .7611 .7642 .7673 .7704 .7734 .7764 .7794 .7823 .7852 0.70.8 .7881 .7910 .7939 .7967 .7995 .8023 .8051 .8078 .8106 .8133 0.80.9 .8159 .8186 .8212 .8238 .8264 .8289 .8315 .8340 .8365 .8389 0.91.0 .8413 .8438 .8461 .8485 .8508 .8531 .8554 .8577 .8599 .8621 1.01.1 .8643 .8665 .8686 .8708 .8729 .8749 .8770 .8790 .8810 .8830 1.11.2 .8849 .8869 .8888 .8907 .8925 .8944 .8962 .8980 .8997 .9015 1.21.3…
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n = 1041 and x = 584 who said "yes." Use a 95% confidence level. Click the icon to view a table of z scores. a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E. E = (Round to three decimal places as needed.) c) Construct the confidence interval.
Determine the area under the standard normal curve that lies to the right of the z-score of 0.81 z 0.00 0.0 0.00.03 0.04 0.05 0.06 0.07 0.08 0.09 0.7 0.7580 0.7611 0.7642 0.7673 0.7704 0.7734 0.7764 0.7794 0.7823 0.7852 0.80.7881 0.7910 0.7939 0.7967 0.7995 0.8023 0.8051 0.8078 0.8106 0.8133 0.90.8159 0.8186 0.8212 0.8238 0.8264 0.8289 0.8315 0.8340 0.8365 0.8389 Use the value(s) from the table above.
Use the Z Table to find the Z score that corresponds to the Z area = .8212 (A) 0.85 (B) ̶ 1.64 (C) 0.92 (D) 1.28