Use the following sample to estimate a population mean μ.25.2 13.4 10.1 49.329.5-11 37.150.328.821.1 25.820.5-5.626.94.437.726.3722.237.937.23.123.931.846.8-5.721.629.1-7.916.932.445.914.1-17.3 23.7 27.144.836.831.72522.5 24.544.617.143.8 13.225.511.640.223.135.74419.645.6 31.940.8Download CSVFind the 80% confidence interval about the populationmean. Enter your answer as a tri-linear inequality accurateto two decimal place.<μ <

The question is about confidence interval.Given :No. of observations in the sample ( n ) = 56

Answered: Use the following sample to estimate a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A statistical program is recommended. A paper gave the following data on n = 11 female black bears. Age(years) Weight(kg) Home-RangeSize (km2) 10.5 54 43.0 6.5 40 46.6 28.5 62 57.4 6.5 55 35.7 7.5 56 62.0 6.5 62 33.8 5.5 42 39.7 7.5 40 32.3 11.5 59 57.2 9.5 51 24.3 5.5 50 68.6 (a) Fit a multiple regression model to describe the relationship between y = home-range size and the predictors x1 = age and x2 = weight. (Round your numerical values to four decimal places.) = (b) If appropriate, carry out a model utility test with a significance level of 0.05 to determine if at least one of the predictors age and weight is useful for predicting home range size. State the null and alternative hypotheses. H0: ?1 = ?2 = 1Ha: at least one of ?1 or ?2 is not 1.H0: At least one of ?1 or ?2 is not 1.Ha: ?1 = ?2 = 1 H0: ?1 = ?2 = 0Ha: at least one of ?1 or ?2 is not 0.H0: At least one of ?1 or ?2 is not 0.Ha: ?1 = ?2 = 0 Calculate the test…
Here is a sample data set that appears to be nearly normal (as suggested by the histogram). 85.4 63.6 85.7 85.6 92.4 89.8 84.2 82.2 88 76.5 87.6 79 61.4 88.6 89.4 95 96.4 76.3 92.4 79.8 82.2 86.5 76.7 90.7 85.4 94 75.8 79.8 92.4 74.3 65 81.4 75.5 76.7 76.5 84.2 78.6 82.9 84.7 74.9 84 91.2 84.4 68.2 76 75.8 74.6 77.3 79.8 69.2 82.9 74.6 71.7 76.7 80 82.2 91.8 74.9 72.7 74.8 84 80.6 67.6 71.7 79.6 81.2 78.2 83.7 82.2 71.4 What is the mean of this data set? (Report answer using the rules suggested in class: 1 more d.p. than the data.)M=What is the standard deviation of this data set? (Report answer using the rules suggested in class: 2 more d.p. than the data.)SD=
Use the following sample to estimate a population mean µ. 11.7 6.6 22.6 41.4 26.9 -0.7 30.2 -7.9 -1.1 20.8 13.3 46.5 -13.4 30.2 6.2 17.3 19 13.1 9.7 17.7 1.7 26.1 2.1 57.8 40.3 46.4 9.4 7.5 11.3 -5.8 1.3 -0.5 12.1 19.2 15.6 25.4 24.4 50.7 0.4 6.8 24.2 24.8 24.5 Download CSV Find the 99% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place. < µ< N327 -43 4
PRACTICE ANOTHER The following data represent crime rates per 1000 population for a random sample of 46 Denver neighborhoods.† 63.2 36.3 26.2 53.2 65.3 32.0 65.0 66.3 68.9 35.2 25.1 32.5 54.0 42.4 77.5 123.2 66.3 92.7 56.9 77.1 27.5 69.2 73.8 71.5 58.5 67.2 78.6 33.2 74.9 45.1 132.1 104.7 63.2 59.6 75.7 39.2 69.9 87.5 56.0 154.2 85.5 77.5 84.7 24.2 37.5 41.1 (a) Use a calculator with mean and sample standard deviation keys to find the sample mean x and sample standard deviation s. (Round your answers to one decimal place.) x = crimes per 1000 people s = crimes per 1000 people (b) Let us say the preceding data are representative of the population crime rates in Denver neighborhoods. Compute an 80% confidence interval for μ, the population mean crime rate for all Denver neighborhoods. (Round your answers to one decimal place.) lower limit crimes per 1000 people upper limit crimes per 1000 people Compute a 95% confidence interval for…
Here is a sample data set. 400 404.8 409.1 409.5 413.1 413.8 418.5 424.7 428.9 432.3 436.1 437.5 440 440 440 441.1 442.4 444.3 445.6 446.1 448 448.8 449.7 450.9 451 453.2 462.3 462.3 462.7 463.6 464.2 465.5 466.7 466.7 467.2 467.7 470.3 472.3 472.6 473.3 473.3 473.3 478.7 479.1 479.3 480.8 485.1 486 490.4 493.1 495.2 496 501.7 506.6 5 10 15 20 25 length (cm) 400 450 500 550 Frequency [Graphs generated by this script: setBorder(54,40,20,15); initPicture(355,550,0,29);axes(1013.2,5,1,null,5); fill="blue"; stroke="black"; textabs([165,0],"length (cm)","above");line([400,-0.58],[400,0.58]); text([400,0],"400","below");line([450,-0.58],[450,0.58]); text([450,0],"450","below");line([500,-0.58],[500,0.58]); text([500,0],"500","below");line([550,-0.58],[550,0.58]); text([550,0],"550","below");textabs([0,115],"Frequency","right",90);rect([400,0],[450,23]);rect([450,0],[500,29]);rect([500,0],[550,2]);] Find the first quartile for this data set. Q1 = 440 Correct Find the third quartile for…
Here is a sample data set. 278.2 282.5 311.5 311.6 320.4 322.9 352.3 367.4 375.7 390.8 395.8 411.7 412.9 412.9 412.9 418.6 419 420.6 423.1 425.2 426.9 429.1 429.6 433.5 434.3 434.8 435.4 435.4 436.2 444 451.7 453 456.5 464.1 473.2 476.1 478.2 489.2 497 502.7 502.7 502.7 513.5 517.9 522.2 566.6 568.3 576.1 577.1 580.8 604.5 618.9 621.6 628.4 24681012141618length (cm)250300350400450500550600650Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(205,650,0,19);axes(1256.8,2,1,null,2); fill="blue"; textabs([165,0],"length (cm)","above");line([250,-0.38],[250,0.38]); text([250,0],"250","below");line([300,-0.38],[300,0.38]); text([300,0],"300","below");line([350,-0.38],[350,0.38]); text([350,0],"350","below");line([400,-0.38],[400,0.38]); text([400,0],"400","below");line([450,-0.38],[450,0.38]); text([450,0],"450","below");line([500,-0.38],[500,0.38]); text([500,0],"500","below");line([550,-0.38],[550,0.38]);…
Here is a sample data set. Frequency 153.1 201.4 209.3 221.3 225.4 228.8 232.8 278.7 282.5 282.6 283.4 290.6 342.9 342.9 342.9 345.2 349.2 358.4 362.8 370.5 379.8 387.9 390.7 403.9 404.3 427.9 434.9 434.9 441.2 443 445 449.4 450.6 460.4 468.5 469.4 480.6 482 489.6 515.6 484.8 488.9 488.9 488.9 525.7 526.5 537.1 537.9 614.3 685.1 739.2 751.7 557.6 599.9 10 8 6 4 2 15000500050005608500050005000 length (cm) Find the first quartile for this data set. Q₁ = Find the third quartile for this data set. Q3= = Find the interquartile range for this data set. IQR = Find the lower fence separating outliers from usual values. Fence low = Find the upper fence separating outliers from usual values. Fence high
The accompanying data below represent the miles per gallon of a random sample of cars with a three-cylinder, 1.0 liter engine. 32.7 35.7 38.0 38.7 40.2 42.1 34.1 36.4 38.1 39.1 40.6 42.9 34.5 37.4 38.3 39.5 41.4 43.4 35.6 37.7 38.6 39.6 41.6 48.9 Compute the z-score corresponding to the individual who obtained 37.4 miles per gallon. Interpret this result. The z-score corresponding to the individual is ____ and indicates that the data value is _____ standard deviation(s) above/below the mean/median (Type integers or decimals rounded to two decimal places as needed.)
Use the following sample to estimate a population mean . 70.6 77.8 65.1 72.1 57.7 53.6 40.6 53.5 38.9 68.1 99 68.8 64.8 59.3 89.2 52.4 100.9 97.9 47.7 60.3 52.4 63.5 65.2 119.4 62.5 103.5 90.1 88.1 49.8 61.2 81.9 20.9 72 59.1 83.2 73.8 62.8 119.9 55.1 88.5 103.2 86.6 Download CSV 55.7 96.3 115.9 Find the 80% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place.
Mouse weights. Find the mean and median for the data in the following table. Interval 41.5−43.5 43.5−45.5 45.5−47.5 47.5−49.5 49.5−51.5 51.5−53.5 53.5−55.5 55.5−57.5 57.5−59.5 Frequency 4 5 14 18 21 15 16 5 2 mean = ______. (Round to two decimal places if needed.)

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