Below is a sample quantitative data set.457.8 386.6 302.3 399.5 425.7293.9 392.2459.1 416.9387.4388.4 414.1431.9374480.6481.4401401420.9 439.4439.4 383.9 291.4484.6352383.7 382.5 514.5 383.7431.2386.3420 386.9422.4409344.3 369.1 503.5511.4 315.1383.7326.3431392 291.3a. Find the first quartile for this data set.Q₁=b. Find the third quartile for this data set.Q3=474.9400.7516.5439.4517.4386.2433289467.4c. Find the interquartile range for this data set.IQR =

From the provided information,Number of observations (n) = 54Arranging the data into ascending…

Answered: Below is a sample quantitative data…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

You intend to estimate a population mean u from the following sample. 27.1 25.6 52.6 44.2 27.6 54.8 85.2 26.8 61.4 94.4 56.5 75.5 18.8 58.8 28.6 28.1 36.5 104.4 18.5 32.9 40 34.2 -1.5 44 85.5 64.7 28.8 10.1 37.9 50.9 6.6 49.1 82 74.1 74.1 12.9 54.1 67.4 94.5 56.6 75.6 43.4 62.7 32.9 34.6 1.2 24.8 Find the 99.9% confidence interval. Enter your answer as a tri-linear inequality accurate to two decimal place (because the sample data are reported accurate to one decimal place). Answer should be obtained without any preliminary rounding. However, the critical value may be rounded to 3 decimal places.
Here is a sample data set. Frequency = 238.4 238.6 272.3 280.6 288.1 291.1 296.8 303.8 308.5 316.5 320.1 360.4 360.4 360.4 363.9 364.3 377.1 378.6 380.4 381.6 388.1 390.2 392.1 404.2 405.3 405.3 406.1 408.5 409 412.4 414.4 416.1 419.7 419.8 422 423.8 424.6 424.6 424.6 427 430.7 439.9 440 459.7 466 471 488.1 491 494.9 498.4 508.1 420.8 = 20 15 10 Find the first quartile for this data set. Q₁ = 5 200 250 300 350 400 450 500 550 length (cm) Find the third quartile for this data set. Q3 Find the interquartile range for this data set. IQR 339 368 Find the lower fence separating outliers from usual values. Fence Low = Find the upper fence separating outliers from usual values. Fence high =
The mean price for used cars is $10,145 . A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car sales at the dealership in an attempt to determine whether the population mean price for used cars at this particular dealership differed from the national mean. The prices for the sample of 50 cars are shown in the table below. 11,359 10,829 10,380 11,454 13,176 8,397 12,559 6,594 11,558 12,653 10,750 6,319 12,018 11,176 11,644 8,221 12,408 11,007 10,063 8,583 12,736 8,142 12,681 6,435 6,297 6,906 11,064 12,476 12,103 6,240 6,668 7,427 13,041 11,237 7,131 10,306 8,228 10,245 7,683 9,775 11,166 6,524 6,487 8,317 11,815 9,836 10,249 11,173 7,156 8,307 b. What is the p-value? Enter negative value if your answer is negative. t-value (to 3 decimals)
According to the National Automobile Dealers Association, the mean price for used cars is $10,192. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car sales at the dealership in an attempt to determine whether the population mean price for used cars at this particular dealership is below the national mean. The prices for the sample of 50 cars are shown in the file named UsedCars. 12400 10400 12100 10000 11000 8895 7675 9975 6350 10470 9895 11250 8795 12500 9340 10150 9200 9395 11000 10640 10000 7500 8000 10440 10200 10300 9740 9280 10930 8000 9000 7680 9400 10730 7350 12240 11970 8240 9910 10080 9440 8970 9500 10050 10130 11400 8500 7500 9090 10500 d. Report the critical value(s) associated with a 5% level of significance. What is your decision based on the critical value approach? (Reject Ho or fail to reject Ho?) e. Compute the p-value of the…
Here is a sample data set (n = 48) that is nearly normal. 51 52 44.4 46.9 48.2 48.8 52 52.4 52.4| 53.4 51 53.5 54.3 55.1 57.3 58.2 58.4 58.6 58.6 58.8 59.2 60.5 60.8 61.4 61.8 62.7 63.3 63.5 64.2 65.7 65.7 66.2 66.9 67.6 69.8 70.3 70.7 72.7 73.2 67 68.3 74 How many outliers are in this data set? ans = 52 57.3 59.8 63.5 68 77.8
4. Given the following 25 sample observations: 5.3, 6.1, 6.7, 6.8, 6.9, 7.2, 7.6, 7.9, 8.1, 8.9, 9.0, 9.2, 9.4, 9.7, 10.1, 10.4, 10.6, 10.8, 11.3, 11.4, 12.0, 12.1, 12.3, 12.5, 13.2 And let Y₁, Y2,, Y be the order statistics for this sample A) The interval (Y9, Y16) could serve as distribution-free estimate of the median, m, of the population. Find the confidence coefficient of this interval. (6 points) B) The interval (Y3, Y10) be a confidence interval for π 25. Determine this confidence interval and, Using Table II in Appendix B of the textbook. Determine the confidence coefficient of this interval.
Here is a sample data set. DO THIS BY HAND, WITHOUT USING TECHNOLOGY. 334.9 337.5 340.2 352.8 356.2 356.3 360.3 361.4 363.9 366.6 367.9 369.7 371.4 371.4 371.4 371.5 371.8 372.3 373.4 373.5 375.5 375.9 378.9 379 380.3 380.3 381.3 381.3 384.9 387.4 388.7 389 392.1 393.3 393.7 394.6 394.6 396.6 397.4 397.5 397.5 397.5 400.1 406.1 420.2 429.1 429.5 430 432 441.2 445 445.9 447.3 449.7 Find the first quartile for this data set.Q1 = Find the third quartile for this data set.Q3 = Find the interquartile range for this data set. IQR = Q3 - Q1IQR =
None
Here is a sample data set. 400 404.8 409.1 409.5 413.1 413.8 418.5 424.7 428.9 432.3 436.1 437.5 440 440 440 441.1 442.4 444.3 445.6 446.1 448 448.8 449.7 450.9 451 453.2 462.3 462.3 462.7 463.6 464.2 465.5 466.7 466.7 467.2 467.7 470.3 472.3 472.6 473.3 473.3 473.3 478.7 479.1 479.3 480.8 485.1 486 490.4 493.1 495.2 496 501.7 506.6 5 10 15 20 25 length (cm) 400 450 500 550 Frequency [Graphs generated by this script: setBorder(54,40,20,15); initPicture(355,550,0,29);axes(1013.2,5,1,null,5); fill="blue"; stroke="black"; textabs([165,0],"length (cm)","above");line([400,-0.58],[400,0.58]); text([400,0],"400","below");line([450,-0.58],[450,0.58]); text([450,0],"450","below");line([500,-0.58],[500,0.58]); text([500,0],"500","below");line([550,-0.58],[550,0.58]); text([550,0],"550","below");textabs([0,115],"Frequency","right",90);rect([400,0],[450,23]);rect([450,0],[500,29]);rect([500,0],[550,2]);] Find the first quartile for this data set. Q1 = 440 Correct Find the third quartile for…
Here is a sample data set. 278.2 282.5 311.5 311.6 320.4 322.9 352.3 367.4 375.7 390.8 395.8 411.7 412.9 412.9 412.9 418.6 419 420.6 423.1 425.2 426.9 429.1 429.6 433.5 434.3 434.8 435.4 435.4 436.2 444 451.7 453 456.5 464.1 473.2 476.1 478.2 489.2 497 502.7 502.7 502.7 513.5 517.9 522.2 566.6 568.3 576.1 577.1 580.8 604.5 618.9 621.6 628.4 24681012141618length (cm)250300350400450500550600650Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(205,650,0,19);axes(1256.8,2,1,null,2); fill="blue"; textabs([165,0],"length (cm)","above");line([250,-0.38],[250,0.38]); text([250,0],"250","below");line([300,-0.38],[300,0.38]); text([300,0],"300","below");line([350,-0.38],[350,0.38]); text([350,0],"350","below");line([400,-0.38],[400,0.38]); text([400,0],"400","below");line([450,-0.38],[450,0.38]); text([450,0],"450","below");line([500,-0.38],[500,0.38]); text([500,0],"500","below");line([550,-0.38],[550,0.38]);…
Here is a sample data set. Frequency 153.1 201.4 209.3 221.3 225.4 228.8 232.8 278.7 282.5 282.6 283.4 290.6 342.9 342.9 342.9 345.2 349.2 358.4 362.8 370.5 379.8 387.9 390.7 403.9 404.3 427.9 434.9 434.9 441.2 443 445 449.4 450.6 460.4 468.5 469.4 480.6 482 489.6 515.6 484.8 488.9 488.9 488.9 525.7 526.5 537.1 537.9 614.3 685.1 739.2 751.7 557.6 599.9 10 8 6 4 2 15000500050005608500050005000 length (cm) Find the first quartile for this data set. Q₁ = Find the third quartile for this data set. Q3= = Find the interquartile range for this data set. IQR = Find the lower fence separating outliers from usual values. Fence low = Find the upper fence separating outliers from usual values. Fence high
Use the following sample to estimate a population mean . 70.6 77.8 65.1 72.1 57.7 53.6 40.6 53.5 38.9 68.1 99 68.8 64.8 59.3 89.2 52.4 100.9 97.9 47.7 60.3 52.4 63.5 65.2 119.4 62.5 103.5 90.1 88.1 49.8 61.2 81.9 20.9 72 59.1 83.2 73.8 62.8 119.9 55.1 88.5 103.2 86.6 Download CSV 55.7 96.3 115.9 Find the 80% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place.

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