Here is a sample data set (n = 48) that is nearly normal (as can be seen in the histogram providedafter the data set).15 21 21.8 23.2 23.4 23.8 23.8 24.326 26.9 28.3 28.8 29.1 30.1 30.1 30.430.6 31.7 31.7 32.1 33 33.6 34.8 3636.4 36.8 37.2 37.4 37.7 37.7 37.9 38.138.3 38.5 38.7 38.7 39.4 39.4 39.8 40.443 43.6 44.4 45.3 48.1 48.2 48.2 53.4Frequency16CH22-642141210L15 20 25 30 35 40 45 50 55dataaHow many outliers are in this data set? Use Excel and the definition of outliers as related to z-scores.ans =

The given sample data is nearly normally distributed. Sample size n=48 The objective is to identify…

Answered: Here is a sample data set (n = after…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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2. The data set are 17, 15.12, 15.9, 11, what is the mean value? a. 59.02 b. 14.76 c. 13.75 d. 12.17 3 What is the median
Calculate the sample mean, median and mode for the above sample values.
Here is a sample data set that appears to be nearly normal (as suggested by the histogram). 85.4 63.6 85.7 85.6 92.4 89.8 84.2 82.2 88 76.5 87.6 79 61.4 88.6 89.4 95 96.4 76.3 92.4 79.8 82.2 86.5 76.7 90.7 85.4 94 75.8 79.8 92.4 74.3 65 81.4 75.5 76.7 76.5 84.2 78.6 82.9 84.7 74.9 84 91.2 84.4 68.2 76 75.8 74.6 77.3 79.8 69.2 82.9 74.6 71.7 76.7 80 82.2 91.8 74.9 72.7 74.8 84 80.6 67.6 71.7 79.6 81.2 78.2 83.7 82.2 71.4 What is the mean of this data set? (Report answer using the rules suggested in class: 1 more d.p. than the data.)M=What is the standard deviation of this data set? (Report answer using the rules suggested in class: 2 more d.p. than the data.)SD=
Here is a sample data set (n = 48) that is nearly normal. 51 52 44.4 46.9 48.2 48.8 52 52.4 52.4| 53.4 51 53.5 54.3 55.1 57.3 58.2 58.4 58.6 58.6 58.8 59.2 60.5 60.8 61.4 61.8 62.7 63.3 63.5 64.2 65.7 65.7 66.2 66.9 67.6 69.8 70.3 70.7 72.7 73.2 67 68.3 74 How many outliers are in this data set? ans = 52 57.3 59.8 63.5 68 77.8
Here is a set of sample data 2 4 7 10 12 22 25 27 34 35 37 38 39 42 47 53 54 55 59 77 85 86 94 Identify the 5 number summary (min, Q1, median, Q3, max)
Here is a sample data set. DO THIS BY HAND, WITHOUT USING TECHNOLOGY. 334.9 337.5 340.2 352.8 356.2 356.3 360.3 361.4 363.9 366.6 367.9 369.7 371.4 371.4 371.4 371.5 371.8 372.3 373.4 373.5 375.5 375.9 378.9 379 380.3 380.3 381.3 381.3 384.9 387.4 388.7 389 392.1 393.3 393.7 394.6 394.6 396.6 397.4 397.5 397.5 397.5 400.1 406.1 420.2 429.1 429.5 430 432 441.2 445 445.9 447.3 449.7 Find the first quartile for this data set.Q1 = Find the third quartile for this data set.Q3 = Find the interquartile range for this data set. IQR = Q3 - Q1IQR =
Here is a sample data set. 400 404.8 409.1 409.5 413.1 413.8 418.5 424.7 428.9 432.3 436.1 437.5 440 440 440 441.1 442.4 444.3 445.6 446.1 448 448.8 449.7 450.9 451 453.2 462.3 462.3 462.7 463.6 464.2 465.5 466.7 466.7 467.2 467.7 470.3 472.3 472.6 473.3 473.3 473.3 478.7 479.1 479.3 480.8 485.1 486 490.4 493.1 495.2 496 501.7 506.6 5 10 15 20 25 length (cm) 400 450 500 550 Frequency [Graphs generated by this script: setBorder(54,40,20,15); initPicture(355,550,0,29);axes(1013.2,5,1,null,5); fill="blue"; stroke="black"; textabs([165,0],"length (cm)","above");line([400,-0.58],[400,0.58]); text([400,0],"400","below");line([450,-0.58],[450,0.58]); text([450,0],"450","below");line([500,-0.58],[500,0.58]); text([500,0],"500","below");line([550,-0.58],[550,0.58]); text([550,0],"550","below");textabs([0,115],"Frequency","right",90);rect([400,0],[450,23]);rect([450,0],[500,29]);rect([500,0],[550,2]);] Find the first quartile for this data set. Q1 = 440 Correct Find the third quartile for…
Here is a sample data set. 278.2 282.5 311.5 311.6 320.4 322.9 352.3 367.4 375.7 390.8 395.8 411.7 412.9 412.9 412.9 418.6 419 420.6 423.1 425.2 426.9 429.1 429.6 433.5 434.3 434.8 435.4 435.4 436.2 444 451.7 453 456.5 464.1 473.2 476.1 478.2 489.2 497 502.7 502.7 502.7 513.5 517.9 522.2 566.6 568.3 576.1 577.1 580.8 604.5 618.9 621.6 628.4 24681012141618length (cm)250300350400450500550600650Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(205,650,0,19);axes(1256.8,2,1,null,2); fill="blue"; textabs([165,0],"length (cm)","above");line([250,-0.38],[250,0.38]); text([250,0],"250","below");line([300,-0.38],[300,0.38]); text([300,0],"300","below");line([350,-0.38],[350,0.38]); text([350,0],"350","below");line([400,-0.38],[400,0.38]); text([400,0],"400","below");line([450,-0.38],[450,0.38]); text([450,0],"450","below");line([500,-0.38],[500,0.38]); text([500,0],"500","below");line([550,-0.38],[550,0.38]);…
Here is a sample data set. 254.2 338.4 218.7 271.8 403.4 339.5 403.6 393.5 339.2 438 362.3 455 404.9 356.3 267.2 367.7 387.7 352.2 397.7 358.5 288.8 411 372.8 357.4 344.7 410.3 446.2 289.1 367.7 453 404.9 349 420.2 255.4 404.5 284.4 310 363 338.4 338.4 443.8 260.5 472.4 356.6 285.3 439.1 403.8 478.1 432 376.8 388.8 389.3 322.5 404.9 Find the first quartile for this data set. Q1 Find the third quartile for this data set. Q3 = Find the interquartile range for this data set. IQR =
Here is a sample data set. Frequency 153.1 201.4 209.3 221.3 225.4 228.8 232.8 278.7 282.5 282.6 283.4 290.6 342.9 342.9 342.9 345.2 349.2 358.4 362.8 370.5 379.8 387.9 390.7 403.9 404.3 427.9 434.9 434.9 441.2 443 445 449.4 450.6 460.4 468.5 469.4 480.6 482 489.6 515.6 484.8 488.9 488.9 488.9 525.7 526.5 537.1 537.9 614.3 685.1 739.2 751.7 557.6 599.9 10 8 6 4 2 15000500050005608500050005000 length (cm) Find the first quartile for this data set. Q₁ = Find the third quartile for this data set. Q3= = Find the interquartile range for this data set. IQR = Find the lower fence separating outliers from usual values. Fence low = Find the upper fence separating outliers from usual values. Fence high
Use the following sample to estimate a population mean . 70.6 77.8 65.1 72.1 57.7 53.6 40.6 53.5 38.9 68.1 99 68.8 64.8 59.3 89.2 52.4 100.9 97.9 47.7 60.3 52.4 63.5 65.2 119.4 62.5 103.5 90.1 88.1 49.8 61.2 81.9 20.9 72 59.1 83.2 73.8 62.8 119.9 55.1 88.5 103.2 86.6 Download CSV 55.7 96.3 115.9 Find the 80% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place.
Here is a sample data set. 382.3 383 387.8 394.3 395.4 406.1 420.6 421.4 438.2 439.2| 441.4 442 445 445 445 445.3 454.2 454.8 456.2 456.3 465.4 466.3 466.9 474.5 475.4 482.4 488.3 488.3 490.1 | 491.2 491.7 493.3 493.7 495 498.6 498.7 499.9 500.6 501 502 502 502 514.2 521 523.2 525.7 526.4 528.6 530.5 | 560.5 564.5 || 587.5 608 616 20 15 10 5 350 400 450 500 550 600 650 length (cm) Find the minimum for this data set. min = Find the first quartile for this data set. Frequency

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