Use the following sample to estimate a population mean u. 6 20.6 29.2 31.3 35.5 18.3 18.8 29.6 48.8 29.3 34.4 36.3 4.7 3 29.4 13.1 34.8 21.8 45.4 33.8 17.4 39.1 55.1 17.3 29.7 39.1 11.8 18.1 33.1 26.2 37.4 40.7 39 16.3 22.2 26.2 16.3 57.5 19.7 20.4 15.8 42 30.4 19.4 24.6 22.5 35.1 27.5 45.5 26 14.9 44.1 35.7 Download CSV Find the 90% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place.

Use the following sample to estimate a population mean u. 6 20.6 29.2 31.3 35.5 18.3 18.8 29.6 48.8 29.3 34.4 36.3 4.7 3 29.4 13.1 34.8 21.8 45.4 33.8 17.4 39.1 55.1 17.3 29.7 39.1 11.8 18.1 33.1 26.2 37.4 40.7 39 16.3 22.2 26.2 16.3 57.5 19.7 20.4 15.8 42 30.4 19.4 24.6 22.5 35.1 27.5 45.5 26 14.9 44.1 35.7 Download CSV Find the 90% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place.

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Description: Use the following sample to estimate a population mean u.620.629.231.335.518.318.829.648.829.334.436.34.7329.413.134.821.845.433.817.439.155.117.329.739.111.818.133.126.237.440.73916.322.226.216.357.519.720.415.84230.419.424.622.535.127.545.52614.94

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The mean cost of a meal for two in a midrange restaurant in City A is $40. How do prices for comparable meals in Hong Kong compare? The file HongKongMeals contains the costs for a sample of 42 recent meals for two in Hong Kong midrange restaurants. 22.78 33.89 22.77 18.04 23.29 35.28 42.38 36.88 38.55 41.68 25.73 34.19 31.75 25.24 26.32 19.57 36.57 32.97 36.83 30.17 37.29 25.37 24.71 28.79 32.83 43.00 35.23 34.76 33.06 27.73 31.89 38.47 39.42 40.72 43.92 36.51 45.25 33.51 29.17 30.54 26.74 37.93 (a) With 95% confidence, what is the margin of error for the estimated mean cost in dollars for a mid-range meal for two in Hong Kong? (Round your answer to the nearest cent.) $ (b) What is the 95% confidence interval estimate of the population mean cost in dollars for a mid-range meal for two in Hong Kong? (Round your answers to the nearest cent.) $ to $ (c) How do prices for meals for two in mid-range restaurants in Hong Kong compare to prices for comparable…
Here is a sample data set that appears to be nearly normal (as suggested by the histogram). 85.4 63.6 85.7 85.6 92.4 89.8 84.2 82.2 88 76.5 87.6 79 61.4 88.6 89.4 95 96.4 76.3 92.4 79.8 82.2 86.5 76.7 90.7 85.4 94 75.8 79.8 92.4 74.3 65 81.4 75.5 76.7 76.5 84.2 78.6 82.9 84.7 74.9 84 91.2 84.4 68.2 76 75.8 74.6 77.3 79.8 69.2 82.9 74.6 71.7 76.7 80 82.2 91.8 74.9 72.7 74.8 84 80.6 67.6 71.7 79.6 81.2 78.2 83.7 82.2 71.4 What is the mean of this data set? (Report answer using the rules suggested in class: 1 more d.p. than the data.)M=What is the standard deviation of this data set? (Report answer using the rules suggested in class: 2 more d.p. than the data.)SD=
Here is a sample data set (n = 48) that is nearly normal. 51 52 44.4 46.9 48.2 48.8 52 52.4 52.4| 53.4 51 53.5 54.3 55.1 57.3 58.2 58.4 58.6 58.6 58.8 59.2 60.5 60.8 61.4 61.8 62.7 63.3 63.5 64.2 65.7 65.7 66.2 66.9 67.6 69.8 70.3 70.7 72.7 73.2 67 68.3 74 How many outliers are in this data set? ans = 52 57.3 59.8 63.5 68 77.8
Use the following sample to estimate a population mean µ. 11.7 6.6 22.6 41.4 26.9 -0.7 30.2 -7.9 -1.1 20.8 13.3 46.5 -13.4 30.2 6.2 17.3 19 13.1 9.7 17.7 1.7 26.1 2.1 57.8 40.3 46.4 9.4 7.5 11.3 -5.8 1.3 -0.5 12.1 19.2 15.6 25.4 24.4 50.7 0.4 6.8 24.2 24.8 24.5 Download CSV Find the 99% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place. < µ< N327 -43 4
4. Given the following 25 sample observations: 5.3, 6.1, 6.7, 6.8, 6.9, 7.2, 7.6, 7.9, 8.1, 8.9, 9.0, 9.2, 9.4, 9.7, 10.1, 10.4, 10.6, 10.8, 11.3, 11.4, 12.0, 12.1, 12.3, 12.5, 13.2 And let Y₁, Y2,, Y be the order statistics for this sample A) The interval (Y9, Y16) could serve as distribution-free estimate of the median, m, of the population. Find the confidence coefficient of this interval. (6 points) B) The interval (Y3, Y10) be a confidence interval for π 25. Determine this confidence interval and, Using Table II in Appendix B of the textbook. Determine the confidence coefficient of this interval.
Here is a sample data set. DO THIS BY HAND, WITHOUT USING TECHNOLOGY. 334.9 337.5 340.2 352.8 356.2 356.3 360.3 361.4 363.9 366.6 367.9 369.7 371.4 371.4 371.4 371.5 371.8 372.3 373.4 373.5 375.5 375.9 378.9 379 380.3 380.3 381.3 381.3 384.9 387.4 388.7 389 392.1 393.3 393.7 394.6 394.6 396.6 397.4 397.5 397.5 397.5 400.1 406.1 420.2 429.1 429.5 430 432 441.2 445 445.9 447.3 449.7 Find the first quartile for this data set.Q1 = Find the third quartile for this data set.Q3 = Find the interquartile range for this data set. IQR = Q3 - Q1IQR =
Here is a sample data set. 400 404.8 409.1 409.5 413.1 413.8 418.5 424.7 428.9 432.3 436.1 437.5 440 440 440 441.1 442.4 444.3 445.6 446.1 448 448.8 449.7 450.9 451 453.2 462.3 462.3 462.7 463.6 464.2 465.5 466.7 466.7 467.2 467.7 470.3 472.3 472.6 473.3 473.3 473.3 478.7 479.1 479.3 480.8 485.1 486 490.4 493.1 495.2 496 501.7 506.6 5 10 15 20 25 length (cm) 400 450 500 550 Frequency [Graphs generated by this script: setBorder(54,40,20,15); initPicture(355,550,0,29);axes(1013.2,5,1,null,5); fill="blue"; stroke="black"; textabs([165,0],"length (cm)","above");line([400,-0.58],[400,0.58]); text([400,0],"400","below");line([450,-0.58],[450,0.58]); text([450,0],"450","below");line([500,-0.58],[500,0.58]); text([500,0],"500","below");line([550,-0.58],[550,0.58]); text([550,0],"550","below");textabs([0,115],"Frequency","right",90);rect([400,0],[450,23]);rect([450,0],[500,29]);rect([500,0],[550,2]);] Find the first quartile for this data set. Q1 = 440 Correct Find the third quartile for…
Here is a sample data set. 278.2 282.5 311.5 311.6 320.4 322.9 352.3 367.4 375.7 390.8 395.8 411.7 412.9 412.9 412.9 418.6 419 420.6 423.1 425.2 426.9 429.1 429.6 433.5 434.3 434.8 435.4 435.4 436.2 444 451.7 453 456.5 464.1 473.2 476.1 478.2 489.2 497 502.7 502.7 502.7 513.5 517.9 522.2 566.6 568.3 576.1 577.1 580.8 604.5 618.9 621.6 628.4 24681012141618length (cm)250300350400450500550600650Frequency[Graphs generated by this script: setBorder(54,40,20,15); initPicture(205,650,0,19);axes(1256.8,2,1,null,2); fill="blue"; textabs([165,0],"length (cm)","above");line([250,-0.38],[250,0.38]); text([250,0],"250","below");line([300,-0.38],[300,0.38]); text([300,0],"300","below");line([350,-0.38],[350,0.38]); text([350,0],"350","below");line([400,-0.38],[400,0.38]); text([400,0],"400","below");line([450,-0.38],[450,0.38]); text([450,0],"450","below");line([500,-0.38],[500,0.38]); text([500,0],"500","below");line([550,-0.38],[550,0.38]);…
Use the following sample to estimate a population mean . 70.6 77.8 65.1 72.1 57.7 53.6 40.6 53.5 38.9 68.1 99 68.8 64.8 59.3 89.2 52.4 100.9 97.9 47.7 60.3 52.4 63.5 65.2 119.4 62.5 103.5 90.1 88.1 49.8 61.2 81.9 20.9 72 59.1 83.2 73.8 62.8 119.9 55.1 88.5 103.2 86.6 Download CSV 55.7 96.3 115.9 Find the 80% confidence interval about the population mean. Enter your answer as a tri-linear inequality accurate to two decimal place.
team 1 9.11 9.22 9.5 9.62 9.68 9.59 team 2 9.7 9.8 9.8 9.81 9.85 team 3 9.88 9.89 9.9 9.9 9.9 10.01 9.85 team 4 9.91 9.91 9.94 9.95 team 5 9.96 9.96 9.96 9.97 9.98 Select the most diverse data. Is it statistically different at the 90% confidence level? Use the appropriate t-test
The following data represent exam scores in a statistics class taught using traditional lecture and a class taught using a "flipped" classroom. Complete parts (a) through (c) below. Traditional 69.9 69.6 78.7 67,6 84.7 78.5 56.3 80.2 81.9 71.0 64.4 70.2 59.0 Flipped 77.5 72.5 62.7 72.6 76.9 90.4 79.6 77.4 81.9 70.5 91.3 77.8 75.7 (a) Which course has more dispersion in exam scores using the range as the measure of dispersion? The traditional course has a range of 28.4 , while the "flipped" course has a range of 28.6. The flipped course has more dispersion. (Type integers or decimals. Do not round.) (b) Which course has more dispersion in exam scores using the sample standard deviation as the measure of dispersion? The traditional course has a standard deviation of, while the "flipped" course has a standard deviation of The V course has more dispersion. (Round to three decimal places as needed.)
1. A sample of 11 individuals shows the following monthly incomes. Individual Income $ 1,500 2,000 1 2 3 2,500 4,000 4,000 2,500 2,000 4,000 3,500 3,000 43,000 4 5 7 8. 9. 10 11 Do you think the mean is a good representative measure of central location for the above data? Explain. a. b. Determine the mode. c. Determine the median. d. Determine the 60th percentile.