Use Kirchhoff's junction rule and voltage/loop rule to find the current through each resistor in the following circuit: RAB = 10 2, RBC = 15 N, RAD = 6 2, RCD = 12 Q, RG = 4 2, and V. = 10 V. The Galvanometer G is a device with a small resistance that measures the current going through RG.

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Apply the Junction Rule at B to determine the current going through RBC in terms of I1 and I3 .

**Step 6: Solving Circuit Equations in a Wheatstone Bridge Network**

In this step, you are tasked with solving the circuit equations for the Wheatstone bridge configuration shown in the diagram. Your goal is to find the currents \( I_1, I_2, \) and \( I_3 \). Be sure to document your calculations in detail.

**Diagram Explanation:**

This diagram represents a Wheatstone bridge circuit, a common configuration used to measure unknown resistances. The circuit comprises four resistors \( R_{AB}, R_{BC}, R_{CD}, \) and \( R_{AD} \), arranged in a diamond shape. There is an additional galvanometer \( G \) between points B and D. Each resistor and the galvanometer contribute to the total resistance and potential difference in the circuit.

- **Points and Connections:**
  - Points are labeled as A, B, C, D, F, H, and K.
  - The battery voltage \( V_o \) is connected across points F and K.
  - Arrows indicate the direction of current flow: \( I_1 \) flows from A to B, \( I_2 \) from A to D, and \( I_3 \) within the galvanometer from B to D.
  
**Kirchhoff's Loop Rule:**

Use Kirchhoff's loop rule to set up equations for each loop in the circuit:
   
1. **Loop ABGH:**
   \[
   V_{o} = I_1 \cdot R_{AB} + I_3 \cdot R_G
   \]

2. **Loop BCDH:**
   \[
   I_3 \cdot R_G = I_3 \cdot R_{BC} + I_3 \cdot R_{CD}
   \]

3. **Loop ADGH:**
   \[
   I_2 \cdot R_{AD} = I_2 \cdot R_{CD} + I_3 \cdot R_G
   \]

Solve these equations simultaneously to find the values of \( I_1, I_2, \) and \( I_3 \). 

Note: The bridge is balanced when the voltage across the galvanometer is zero, meaning \( I_3 = 0 \). Use this condition to simplify calculations when relevant.
Transcribed Image Text:**Step 6: Solving Circuit Equations in a Wheatstone Bridge Network** In this step, you are tasked with solving the circuit equations for the Wheatstone bridge configuration shown in the diagram. Your goal is to find the currents \( I_1, I_2, \) and \( I_3 \). Be sure to document your calculations in detail. **Diagram Explanation:** This diagram represents a Wheatstone bridge circuit, a common configuration used to measure unknown resistances. The circuit comprises four resistors \( R_{AB}, R_{BC}, R_{CD}, \) and \( R_{AD} \), arranged in a diamond shape. There is an additional galvanometer \( G \) between points B and D. Each resistor and the galvanometer contribute to the total resistance and potential difference in the circuit. - **Points and Connections:** - Points are labeled as A, B, C, D, F, H, and K. - The battery voltage \( V_o \) is connected across points F and K. - Arrows indicate the direction of current flow: \( I_1 \) flows from A to B, \( I_2 \) from A to D, and \( I_3 \) within the galvanometer from B to D. **Kirchhoff's Loop Rule:** Use Kirchhoff's loop rule to set up equations for each loop in the circuit: 1. **Loop ABGH:** \[ V_{o} = I_1 \cdot R_{AB} + I_3 \cdot R_G \] 2. **Loop BCDH:** \[ I_3 \cdot R_G = I_3 \cdot R_{BC} + I_3 \cdot R_{CD} \] 3. **Loop ADGH:** \[ I_2 \cdot R_{AD} = I_2 \cdot R_{CD} + I_3 \cdot R_G \] Solve these equations simultaneously to find the values of \( I_1, I_2, \) and \( I_3 \). Note: The bridge is balanced when the voltage across the galvanometer is zero, meaning \( I_3 = 0 \). Use this condition to simplify calculations when relevant.
**Kirchhoff's Circuit Analysis**

Use Kirchhoff’s junction rule and voltage/loop rule to find the current through each resistor in the following circuit: \( R_{AB} = 10 \, \Omega \), \( R_{BC} = 15 \, \Omega \), \( R_{AD} = 6 \, \Omega \), \( R_{CD} = 12 \, \Omega \), \( R_G = 4 \, \Omega \), and \( V_o = 10 \, V \).

The Galvanometer \( G \) is a device with a small resistance that measures the current going through \( R_G \).
Transcribed Image Text:**Kirchhoff's Circuit Analysis** Use Kirchhoff’s junction rule and voltage/loop rule to find the current through each resistor in the following circuit: \( R_{AB} = 10 \, \Omega \), \( R_{BC} = 15 \, \Omega \), \( R_{AD} = 6 \, \Omega \), \( R_{CD} = 12 \, \Omega \), \( R_G = 4 \, \Omega \), and \( V_o = 10 \, V \). The Galvanometer \( G \) is a device with a small resistance that measures the current going through \( R_G \).
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