Under Unbalanced Condition Without Faults: a. Load Line Currents (Ia, Ip,I); b. Load Line Voltages (Vab, Vbc, Vca); c. Load Power Profile (Pr, QT,St,pfr).

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Compute using 4 decimal places and use scientific notation when necessary
Box all final answers./
FIND:
1. Under Unbalanced Condition Without Faults:
a. Load Line Currents (Ia, Ip,I);
b. Load Line Voltages (Vab, Vbc, Vca);
c. Load Power Profile (Pr, QT,St,pfr).
2. Under Unbalanced Condition With Faults:
a. Load Line Currents (Ia, Ip, I);
b. Load Line Voltages (Vab, Vpc, Vca);
c. Load Power Profile (Pr, Qr,St, pfr);
d. The Fault Current (If)
Transcribed Image Text:Compute using 4 decimal places and use scientific notation when necessary Box all final answers./ FIND: 1. Under Unbalanced Condition Without Faults: a. Load Line Currents (Ia, Ip,I); b. Load Line Voltages (Vab, Vbc, Vca); c. Load Power Profile (Pr, QT,St,pfr). 2. Under Unbalanced Condition With Faults: a. Load Line Currents (Ia, Ip, I); b. Load Line Voltages (Vab, Vpc, Vca); c. Load Power Profile (Pr, Qr,St, pfr); d. The Fault Current (If)
GIVEN:
Three-phase System Data:
30 Source
Z Line
30 Load
Ean = 12020° v; Epn = 1202 – 120° v; Een = 1204120° v (grounded neutral)
Source:
Zan
Zon = Zen = 0.1 +j1.5 N
%3D
Line Impedance:
Zline a
= Zline
Zline c = 1 + j2 N;
%3D
Load Impedance:
Zab = 40 + j30 N; Zbc = 40 – j30 N; Zca
50 + j0 N
%3D
%3D
Transcribed Image Text:GIVEN: Three-phase System Data: 30 Source Z Line 30 Load Ean = 12020° v; Epn = 1202 – 120° v; Een = 1204120° v (grounded neutral) Source: Zan Zon = Zen = 0.1 +j1.5 N %3D Line Impedance: Zline a = Zline Zline c = 1 + j2 N; %3D Load Impedance: Zab = 40 + j30 N; Zbc = 40 – j30 N; Zca 50 + j0 N %3D %3D
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