#11Normal stress in rods 1 and 2 A(1)B(2)C Two solid cylindrical rods (1) and (2) arejoined together at flange B and loaded, asshown. The diameter of rod (1) is d1= 1.98 in. and the diameter of rod (2) is d2%3D= 3.16 in. Determine the normal stresses inrods (1) and (2). Assume P = 12 kips and Q= 34 kips. Use positive for tensile stressand negative for compressive stress.%3D

Answered: Image /qna-images/answer/c0d3cf7d-e55d-4565-b355-85f50587db89.jpg

Two solid cylindrical rods (1) and (2) are joined together at flange B and loaded, as shown. The diameter of rod (1) is di = 1.98 in. and the diameter of rod (2) is d2 %3D = 3.16 in. Determine the normal stresses in rods (1) and (2). Assume P = 12 kips and Q %3D = 34 kips. Use positive for tensile stress %3D and negative for compressive stress.

Two solid cylindrical rods (1) and (2) are joined together at flange B and loaded, as shown. The diameter of rod (1) is di = 1.98 in. and the diameter of rod (2) is d2 %3D = 3.16 in. Determine the normal stresses in rods (1) and (2). Assume P = 12 kips and Q %3D = 34 kips. Use positive for tensile stress %3D and negative for compressive stress.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

For the section shown, if the distance from the N.A to the steel centroid is 350 mm, 1944.4 x 10^6 mm^4, Es = 200 GPa, Ec = 20 GPa and M = -50 kN.m, then the strain in steel is b P -185.3 MPa O -926 x 10^-6 O 926 x 10^-6 O 185.3 MPa O zero O
to the direction of loading. When When solving for Normal/Axial/Compressive/Tensile Stress we look at an area of our member that is solving for basic Shear Stress we look at an area to the direction of loading. This is because of how the members will fail in either situation and what resists that failure. Parallel, Parallel 1000 Parallel, Perpendicular Perpendicular, Parallel Perpendicular, Perpendicular
1) Figure 1 shows an element with stresses. Angle 1 Oy Tyx Ox Txy Tyx Figure 1 Point Ax-direction stress 60MPA(compression), y-direction stress 40MPA(tension), negative shear stress 30MPA a) From basic priciples determine the stresses on the plane of the indicated angle 1-30°, Show al calculations. Draw the orientation of the stress block for this scenario. b) Repeat question (a) using a Mohr circle.
4.15 Knowing that for the casting shown in the figure the allowable stress is 6 ksi in tension and 15 ksi in compression, determine the maximum couple M that can be applied.
Problem 2. [Concepts: Internal forces in 2D and average normal stress] The bars of the truss each have a cross-sectional area of 1.25 in². a) Determine the average normal stress in each member due to the loading P = 8 kip. State whether the stress is tensile or compressive. b) If the maximum average normal stress in any bar is not to exceed 20 ksi, determine the maximum magnitude P of the loads that can be applied to the truss. 4 ft 4 ft 4 E 0.75 P 0
1.61.The state of stress at a point relative to an x, y, z coordinate system is given by 12 4 2 4 -8 -1 MPа -1 6. Calculate the maximum shearing stress at the point.
The 1.24-in diameter rod is subjected to the loads shown: -Determine normal stress (sigma) at point A -Determine shear stress (Tau_xz) at point A
If the maximum bending stress at section a–a is not allowed to exceed an allowable stress of 220 MPa, determine the maximum allowable force P that can be applied to the end E.
A square bar carries a series of loads as shown in Figure P1-47. Compute the stress in each segment of the bar. All loads act along the central axis of 1-47. the bar.
B1
PLEASE DRAW THE FBD. DO NOT COPY YOUR ANSWER FROM OTHER. I WANT TO SEE THE FBD OF INDIVIDUAL DEFORMATIONS ON HOW YOU WILL ARRIVE ON YOUR ANSWER. DRAW FBD ON EACH PLEASE. NOT ONLY ONE FBD