Discuss and differentiate method 1 and 2 in bending test. 3.2.7(b) Method II: It is four -point loading system utilizing two load points equally spacedfrom their adjacent supports point, with a distance between load points of one-third of the supportspan. In this method, the test bar rests on two supports & is loaded at two point (by means of twoloading noses), each on equal distance from the adjacent support point. This method is veryuseful in testing materials that do not fail at the point of maximum stress under a three-pointloading system the maximum axial fiber stress occurs over the area between the loading noses.22PP22LOADSPAN3LSUPPORTSPANSchematic of specimen arrangement for flexural testing 3.2.7(a) Method I: It is a three-point loading system utilizing center loading on a simplesupported beam. A bar of rectangular cross section rest on two supports & is loaded by means ofa loading nose midway between the support the maximum axial fiber stresses occur on a lineunder loading nose.LoadCompressive forcesNeutral axisForces involved in bendinga simple beam.Tensile forces

Bending: - It is defined as change in position of body or any part of body so that it is no longer…

Answered: Discuss and differentiate method 1 and…

Engineering

Civil Engineering

Discuss and differentiate method 1 and 2 in bending test.

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter9: Composite Construction

Section: Chapter Questions

Problem 9.1.3P

See similar textbooks

Related questions

Q: Three steel bolts were used to attach a steel plate to a wooden beam. The plate is designed to…

Q: Define The ultimate strength design method

A: The ultimate strength design method: There are three design methods: 1.Working stress…

Q: (1) 22² #4 12" 4#8 NWC. fe= 3000 psi, Grade 60 steel (a) Mer=? (b) If M=50 (0) & Mn = ? ft-kips fe &…

A: fc'=3000 psiGrade 60 steel. Calculation of Mcr- We know that cracking Moment is given by Mcr =…

Q: Given the concrete (f c=6000 psi) I-beam shown in Figure 1 for the given loading: -draw the shear &…

A: The cross-section of beam is given by I-section shown below

Q: Footing reinforcement Q- estimate the quantity of reinforcement in ton for 10 footing (square base)…

A: To estimate the quantity of reinforcement in tons for 10 footings with a square base, we need to…

Q: What are the three types of shear tests? Name and describe.

A: The three types of shear tests are- 1. Direct shear test 2. Unconfined compression shear test 3.…

Q: Assuming elastic behavior, why does the maximum shear stress always correspond to the neutral axis…

A: Given data:

Q: 30" Check if the following T-beams satisfy the ACI requirements for T-beams. Regardless of your…

Q: A hole 12 mm diameter is to be punched. through a plate 18 mm thick. If the shear strength of the…

A: Diameter of hole (D) = 12mm Thickness of plate (t) = 18mm Shear strength of material (Su) = 300…

Q: Given the concrete (f =6000 psi) I-beam shown in Figure 1 for the given loading: -draw the shear &…

A: The cross−section of beam is shown below To determine:1. SFD and BMD2. Maximum Shear force and…

Question

Discuss and differentiate method 1 and 2 in bending test.

3.2.7(b) Method II: It is four -point loading system utilizing two load points equally spaced
from their adjacent supports point, with a distance between load points of one-third of the support
span. In this method, the test bar rests on two supports & is loaded at two point (by means of two
loading noses), each on equal distance from the adjacent support point. This method is very
useful in testing materials that do not fail at the point of maximum stress under a three-point
loading system the maximum axial fiber stress occurs over the area between the loading noses.
2
2
P
P
2
2
LOAD
SPAN
3
L
SUPPORT
SPAN
Schematic of specimen arrangement for flexural testing

3.2.7(a) Method I: It is a three-point loading system utilizing center loading on a simple
supported beam. A bar of rectangular cross section rest on two supports & is loaded by means of
a loading nose midway between the support the maximum axial fiber stresses occur on a line
under loading nose.
Load
Compressive forces
Neutral axis
Forces involved in bending
a simple beam.
Tensile forces

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Compute the nominal shear strength of an M107.5 of A572 Grad 65 steel.
A beam is part of the framing system for the floor of an office building. The floor is subjected to both dead loads and live loads. The maximum moment caused by the service dead load is 45 ft-kips, and the maximum moment for the service live load is 63 ft-kips (these moments occur at the same location on the beam and can therefore be combined). a. If load and resistance factor design is used, determine the maximum factored bending moment (required moment strength). What is the controlling AISC load combination? b. What is the required nominal moment strength for a resistance factor of 0.90? c. If allowable strength design is used, determine the required moment strength. What is the controlling AISC lead combination? d. What is the required nominal moment strength for a safety factor of 1.67?
Compute the nominal shear strength of an M1211.8 of A572 Grade 65 steel.
A tensile test was performed on a metal specimen having a circular cross section with a diameter 0. 510 inch. For each increment of load applied, the strain was directly determined by means of a strain gage attached to the specimen. The results are, shown in Table: 1.5.1. a. Prepare a table of stress and strain. b. Plot these data to obtain a stress-strain curve. Do not connect the data points; draw a best-fit straight line through them. c. Determine the modulus of elasticity as the slope of the best-fit line.
The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2011in.2 in area and a gage length (the length over which the elongation is measured) of 2.000 inches. The specimen was not loaded to failure. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2 offset method to determine the yield stress.
A tensile test was performed on a metal specimen with a diameter of 1 2 inch and a gage length (the length over which the elongation is measured) of 4 inches. The dam were plotted on a load-displacement graph. P vs. L. A best-fit line was drawn through the points, and the slope of the straight-line portion was calculated to be P/L =1392 kips/in. What is the modulus of elasticity?
Determine the smallest value of yield stress Fy, for which a W-, M-, or S-shape from Part 1 of the Manual will become slender. To which shapes does this value apply? What conclusion can you draw from your answer?
using Figure 5-27, what is the advantage of the suspended type magnet over the other two types of magnets?
The given beam is laterally supported at the ends and at the 1 3 points (points 1, 2, 3, and 4). The concentrated load is a service live load. Use Fy=50 ksi and select a W-shape. Do not check deflections. a. Use LRFD. b. Use ASD.
A beam must be designed to the following specifications: Span length = 35 ft Beam spacing = 10 ft 2-in. deck with 3 in. of lightweight concrete fill (wc=115 pcf) for a total depth of t=5 in. Total weight of deck and slab = 51 psf Construction load = 20 psf Partition load = 20 psf Miscellaneous dead load = 10 psf Live load = 80 psf Fy=50 ksi, fc=4 ksi Assume continuous lateral support and use LRFD. a. Design a noncomposite beam. Compute the total deflection (there is no limit to be checked). b. Design a composite beam and specify the size and number of stud anchors required. Assume one stud at each beam location. Compute the maximum total deflection as follows: 1. Use the transformed section. 2. Use the lower-bound moment of inertia.
A plate girder must be designed for the conditions shown in Figure P10.7-4. The given loads are factored, and the uniformly distributed load includes a conservative estimate of the girder weight. Lateral support is provided at the ands and at the load points. Use LRFD for that following: a. Select the, flange and web dimensions so that intermediate stiffeners will he required. Use Fy=50 ksi and a total depth of 50 inches. Bearing stiffeners will be used at the ends and at the load points, but do not proportion them. b. Determine the locations of the intermediate stiffeners, but do not proportion them.
Estimate the transverse tensile strength of the concrete in Problem 12.6.