Problem 2. [Concepts: Internal forces in 2D and average normal stress] The bars of the tru each have a cross-sectional area of 1.25 in². a) Determine the average normal stress in each member due to the loading P = 8 kip. Sta whether the stress is tensile or compressive. b) If the maximum average normal stress in any bar is not to exceed 20 ksi, determine t maximum magnitude P of the loads that can be applied to the truss. 4 ft 4 ft "4 E 0.75 P 0
Problem 2. [Concepts: Internal forces in 2D and average normal stress] The bars of the tru each have a cross-sectional area of 1.25 in². a) Determine the average normal stress in each member due to the loading P = 8 kip. Sta whether the stress is tensile or compressive. b) If the maximum average normal stress in any bar is not to exceed 20 ksi, determine t maximum magnitude P of the loads that can be applied to the truss. 4 ft 4 ft "4 E 0.75 P 0
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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![Problem 2. [Concepts: Internal forces in 2D and average normal stress] The bars of the truss
each have a cross-sectional area of 1.25 in².
a) Determine the average normal stress in each member due to the loading P = 8 kip. State
whether the stress is tensile or compressive.
b) If the maximum average normal stress in any bar is not to exceed 20 ksi, determine the
maximum magnitude P of the loads that can be applied to the truss.
4 ft
4 ft
4
E
0.75 P
0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F899fb828-393b-407f-a327-7733d20ede86%2Fdb5ff306-2bde-48e7-9789-e4f4953b2e53%2Fby33zmn_processed.png&w=3840&q=75)
Transcribed Image Text:Problem 2. [Concepts: Internal forces in 2D and average normal stress] The bars of the truss
each have a cross-sectional area of 1.25 in².
a) Determine the average normal stress in each member due to the loading P = 8 kip. State
whether the stress is tensile or compressive.
b) If the maximum average normal stress in any bar is not to exceed 20 ksi, determine the
maximum magnitude P of the loads that can be applied to the truss.
4 ft
4 ft
4
E
0.75 P
0
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