Trial 1 Trial 2 Trial 3 Trial 4 Mass of KHC8H4O4 (KHP) 2.0158 KHP 1.9657 KHP 2.0053 KHP 1.9801 KHP Initial buret reading 0.00 M 0.00 M 0.00 M |0.00 M ww m Final buret reading 31.04 M 30.83 M 30.81 M 30.50 M Volume of NaOH 0.03104 L 0.03083 L 0.03081 L 0.0305 L Results table Trial 1 Trial 2 Trial 3 Trial 4 Moles of KHP 0.00987 0.00962 0.00982 |0.00969 Moles of NaOH 0.00987 0.00962 0.00982 0.00982 Volume of NaOH (L) 0.03104 L 0.03083 L 0.03081 L 0.0305 L Molarity of NaOH 0.31797 3.12033 0.31883 3.2196 L Average molarity of NaOH Sample calculation: In the space below show complete calculations for moles of KHP and molarity of NAOH using data from TRIAL 1 only. Include formulas and units.

Trial 1 Trial 2 Trial 3 Trial 4 Mass of KHC8H4O4 (KHP) 2.0158 KHP 1.9657 KHP 2.0053 KHP 1.9801 KHP Initial buret reading 0.00 M 0.00 M 0.00 M |0.00 M ww m Final buret reading 31.04 M 30.83 M 30.81 M 30.50 M Volume of NaOH 0.03104 L 0.03083 L 0.03081 L 0.0305 L Results table Trial 1 Trial 2 Trial 3 Trial 4 Moles of KHP 0.00987 0.00962 0.00982 |0.00969 Moles of NaOH 0.00987 0.00962 0.00982 0.00982 Volume of NaOH (L) 0.03104 L 0.03083 L 0.03081 L 0.0305 L Molarity of NaOH 0.31797 3.12033 0.31883 3.2196 L Average molarity of NaOH Sample calculation: In the space below show complete calculations for moles of KHP and molarity of NAOH using data from TRIAL 1 only. Include formulas and units.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Fill in the blanks for 1-6
1b Mole calculations Multimedia activities
Toxic Cr(VI) can be precipitated from an aqueous solution by bubbling SO2 through the solution. How much SO2 is required to treat 3.00 x 108 L of 7.00x102 mM Cr(VI)? 2Cro +3S0, +4H* → Cr2(SO4)3+2H,O kg
I need the answers with solut
2. What coefficients would balance the following equation? _C2H6 + _02 –→_CO2+ _H2 O A. 1C2H6 + 502 → 2C02 + 3H20 B. 202H6 + 502→ 4CO2 + 6H20 С. 2С2H6 + 702 4C02 + 6H20 O D. 2C2H6 + 1002 → 4CO2 + 6H2O
Remaining Time: 1 hour, 01 minute, 47 seconds. * Question Completion Status: QUESTION 2 The number of water molecules in 2.3 mg of water is O 6.02 x 1023 O 77.0 x 1023 O 7.7 x 1023 O 7.7 x 1019 none of the above QUESTION 3 A ctudent makes a colution bu discolvina 254a ofNDOH int0 450 gof water Wh. Click Save and Submit to save and submit. Click Save All Answers to save all answer ere to search DELL
+ Chemistry 20 Midterm Equation Sheet (Click to open) Nitric acid is a potentially dangerous strong acid that must be handled with great care. A laboratory technician is asked to dilute a sufficient quantity of stock 15.4 mol/L nitric acid to produce 1.50 L of a 0.220 mol/L solution. Calculate the volume of concentrated nitric acid needed to prepare this diluted solution. XQ F1 BI E E F2 2 E E F3 % F4 F5 U S X₂ x² E F6 II Proctorio is sharing your screen. Ⓡ F7 = I Stop sharing DO LL F8 5 C H Hide + F9 ✓ C F10
Can you answer it as if you where putting it in those boxes. Set the equation up
Answered -Correct! U8HW Question 15 == Homework 11:59 PM Answered Due Mar 19th, Resubmit Reacting water with magnesium nitride produces ammonia (NH3) and magnesium hydroxide. If this process is 70% efficient, what mass of ammonia (in kg) can be prepared from 19.5 kg of magnesium nitride? Type your numeric answer and submit 2.28 Answered - Incorrect U8HW Question 16 K Answered Due Mar 19th, == Homework 11:59 PM ⭑ You are incorrect Resubm Open in Reading
Jeff followed to procedure for Experiment 4, and collected the following data, which he recorded on his "Data and Calculations" sheet: Row A Mass of flask = 97.85 g Row B Mass of flask + unknown = 99.86 g Row C Mass of graduated cylinder + HCl( aq) = 37.470 g Row D Mass of emptied graduated cylinder = 26.941 g Row E Mass of flask containing reaction mixture = 109.55 g What was the mass in grams of the HCl( aq) used by Jeff in this experiment ?
Determine the number of molecules of Cr,0; that form when 1.34 x 103 g of oxygen completely reacts according to the following equation: 4 Cr(s) + 3 O2(g) → 2 Cr2O3(s) STARTING AMOUNT ADD FACTOR ANSWER RESET *( ) |2.52 х 1025 152.00 4.24 x 103 |3.78 х 1025 3 1.68 х 1025 4 6.022 x 1023 1.34 x 10° 52.00 32.00 1 g O2 g Cr203 mol Cr2O3 molecules Cr203 mol Cr g Cr mol O2
WE $ 4 R F Part A What is the minimum amount of 7.0 MH₂SO4 necessary to produce 25.0 g of H₂ (g) according to the following reaction? 2Al(s) + 3H₂SO4 (aq) → Al2(SO4)3(aq) + 3 H₂(g) Express your answer using two significant figures. View Available Hint(s) SO F4 V = Provide Feedback V Submit |Π| ΑΣΦ % 5 T on y F5 G 6 B 4 MacBook Air IS FO Y H & 7 N 8 F7 U ? J L * 00 8 DII FB 1 M ( 9 K F9 O ) O 36 L A F10 11 P AP . V F11 + 11 ?