CHEM 181 Experiment #5 Part B Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NaOH. Trial 1 Trial 2 Trial 3 Mass of flask (g) Mass of flask + vinegar sample 128.315 131.911 (8) Mass of vinegar sample (g) 3.0CC00 Initial buret reading of NaOH (Tu) Final buret reading of NaOH 25.25 2C.05 Volume of NaOH dispensed (mL) [NAOH] (M), average from Part 25.25 26.OS 0.100 Moles of NaOH dispensed Moles of acetic acid in vinegar sample Mass of acetic acid in vinegar eample (g)
CHEM 181 Experiment #5 Part B Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NaOH. Trial 1 Trial 2 Trial 3 Mass of flask (g) Mass of flask + vinegar sample 128.315 131.911 (8) Mass of vinegar sample (g) 3.0CC00 Initial buret reading of NaOH (Tu) Final buret reading of NaOH 25.25 2C.05 Volume of NaOH dispensed (mL) [NAOH] (M), average from Part 25.25 26.OS 0.100 Moles of NaOH dispensed Moles of acetic acid in vinegar sample Mass of acetic acid in vinegar eample (g)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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How do I find the amount of NaOH moles dispensed?
![CHEM 181 Experiment #5
Part B
Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NaOH.
Trial 1
Trial 2
Trial 3
Mass of flask (g)
120.056
125.237
128.321
Mass of flask + vinegar sample
123.122
128.315
(8)
Mass of vinegar sample (g)
131.911
3.0CC00
Initial buret reading of NaOH
(mL)
Final buret reading of NaOH
000
25.25
24.45
2 6.05
(Tu)
Volume of NaOH dispensed
25.25
24.95
26.OS
(m)
[NAOH] (M), average from Part
A
Moles of NaOH dispensed
Moles of acetic acid in vinegar
sample
Mass of acetic acid in vinegar
(土
sample (g)
Percent by mass of acetic acid in
vinegar sample (%)
Average percent by mass of acetic acid in vinegar sample (%)
Standard deviation of percent by mass of acetic acid in vinegar sample (%)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F75a875eb-a6f8-4d83-be2b-1f28f1ef8017%2F43cb4651-16bd-4d1f-9709-1d28093d2677%2F0kds17s_processed.jpeg&w=3840&q=75)
Transcribed Image Text:CHEM 181 Experiment #5
Part B
Calculate the approximate volume of vinegar to react with 25 mL of 0.1 M NaOH.
Trial 1
Trial 2
Trial 3
Mass of flask (g)
120.056
125.237
128.321
Mass of flask + vinegar sample
123.122
128.315
(8)
Mass of vinegar sample (g)
131.911
3.0CC00
Initial buret reading of NaOH
(mL)
Final buret reading of NaOH
000
25.25
24.45
2 6.05
(Tu)
Volume of NaOH dispensed
25.25
24.95
26.OS
(m)
[NAOH] (M), average from Part
A
Moles of NaOH dispensed
Moles of acetic acid in vinegar
sample
Mass of acetic acid in vinegar
(土
sample (g)
Percent by mass of acetic acid in
vinegar sample (%)
Average percent by mass of acetic acid in vinegar sample (%)
Standard deviation of percent by mass of acetic acid in vinegar sample (%)
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