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Solve the equation

Solve the equation

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Solve the equation

Here's the Third, and final, problem. You are doing an experiment in a laboratory that is 23°C and 0.999 atm of pressure. You take a 0.995L flask that weighs 303.121g and fill it with CO2. After it is filled it weighs 303.622g. Calculate the molar volume of the CO₂! VSTP = P₁V₁T STP T₁P STP 0-999*0.995 * 273 296*1 = 0.916 L 1.200 * 0.995 = 1.1949 303.622-303-121 + 1.194 = 1.6959 1.695/44.01 = 0.0385 mol co₂ 0.916/0.0385 = 23.79 L/mol Mass of air = (density of air)(volume of flask) 1-200*0.995 = 1.1949 Mass of CO₂ = (Mass of flask filled with CO₂) - (Mass of empty flask) + (Mass of air) 303-622-303-121 +1-194 = 1.6959
Transcribed Image Text:Here's the Third, and final, problem. You are doing an experiment in a laboratory that is 23°C and 0.999 atm of pressure. You take a 0.995L flask that weighs 303.121g and fill it with CO2. After it is filled it weighs 303.622g. Calculate the molar volume of the CO₂! VSTP = P₁V₁T STP T₁P STP 0-999*0.995 * 273 296*1 = 0.916 L 1.200 * 0.995 = 1.1949 303.622-303-121 + 1.194 = 1.6959 1.695/44.01 = 0.0385 mol co₂ 0.916/0.0385 = 23.79 L/mol Mass of air = (density of air)(volume of flask) 1-200*0.995 = 1.1949 Mass of CO₂ = (Mass of flask filled with CO₂) - (Mass of empty flask) + (Mass of air) 303-622-303-121 +1-194 = 1.6959
Moles of CO₂ = (Mass of CO₂) ÷ (Molar Mass of CO₂) 1.695/44.01 = 0.0385 Molar Volume = VSTP + Moles of CO2 Percent error = | 0.916/0.0385 = 23-79 L/mol experimental value-true value true value True value = 22.4 L/mol x 100 22.4 23.79 * 100 22.4 6.205%
Transcribed Image Text:Moles of CO₂ = (Mass of CO₂) ÷ (Molar Mass of CO₂) 1.695/44.01 = 0.0385 Molar Volume = VSTP + Moles of CO2 Percent error = | 0.916/0.0385 = 23-79 L/mol experimental value-true value true value True value = 22.4 L/mol x 100 22.4 23.79 * 100 22.4 6.205%
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