A 4.70 g quantity of solid rubidium metal is combined with 3.44 g of magnesium chloride crystals according to this mptal chemical reaction: 2 Rb (s) +1 MgCl2 (s) 1Mg (s) +2 RBCI (s) What quantity of magnesium metal will be produced? -g Mg round your answer using appropriate sig figs The following molar masses may or may not be needed, but are provided to save you time: • molar mass: Rb = 85.47 g/mol • molar mass: MgCl2= 95.21 g/mol • molar mass: Mg = 24.31 g/mol Hiint: Start with the number of grams of Rubidium

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A 4.70 g quantity of solid rubidium metal is combined with 3.44 g of magnesium chloride crystals according to this
chemical reaction:
2 Rb (s) + 1 MgCl2 (s)
What quantity of magnesium metal will be produced?
g Mg 'round your answer using appropriate sig figs
I.
1 Mg (s) + 2 RbCI (s)
The following molar masses may or may not be needed, but are provided to save you timer
• molar mass: Rb = 85.47 g/mol
• molar mass: MgCl, = 95.21 g/mol
• molar mass: Mg = 24.31 g/mol
%3D
Hiint: Start with the number of grams of Rubidium
Transcribed Image Text:A 4.70 g quantity of solid rubidium metal is combined with 3.44 g of magnesium chloride crystals according to this chemical reaction: 2 Rb (s) + 1 MgCl2 (s) What quantity of magnesium metal will be produced? g Mg 'round your answer using appropriate sig figs I. 1 Mg (s) + 2 RbCI (s) The following molar masses may or may not be needed, but are provided to save you timer • molar mass: Rb = 85.47 g/mol • molar mass: MgCl, = 95.21 g/mol • molar mass: Mg = 24.31 g/mol %3D Hiint: Start with the number of grams of Rubidium
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