Trial 1Trial 2Trial 3Initial burette reading(mL)1.152.051.14Molarity of NaOH (M)0.1000.1000.100Volume of vinegarsample (mL)5.005.005.00Final burette reading(mL)48.7048.9848.36Choose.Choose.Choose..Expected color at endpointChoose... -Choose...Choose...Volume of NaOH used(mL)Average Volume of NaOH used in liters| Average moles of NaOH used (mol)Average moles of acetic acid (mol)Average molarity of acetic acid (M)Average mass of acetic acid (g)Average mass of vinegar (g) (assume the density of vinegar is1.00 g/mL)) Average mass % of acetic acid in vinegarKnown mass % of acetic acid in vinegar is 5.45% Answer the following questions.) Suppose the concentration of the NaOH solution was 0.5 Minstead of 0.1 M. Would this titration have required more, less,or the same amount of NaOH solution for a completereaction?Choose...:) Suppose you used 0.5 M NaOH to titrate your vinegar sampleinstead of 0.1 M. What effect does the concentration of baseadded have on the reliability of the results of your titration?Choose...Consider a 0.238 M aqueous solution of sodium hydroxide,NaOH.;)Consider a 0.238 M aqueous solution of sodium hydroxide,NaOH.a. How many grams of NaOH are dissolved in 23.46 mL?b. How many individual hydroxide ions (OH") are found in23.46 mL?c. How many moles of sulfuric acid, H2SO4, are neutralizedby 23.46 mL of 0.238 M NaOH(aq)? [Hint: begin bywriting a balanced equation for this neutralizationreaction.]

Answered: Image /qna-images/answer/8b908182-26a6-4734-bd45-f12d0b60fcb6.jpg

Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.15 2.05 1.14 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 48.70 48.98 48.36 Choose.. Choose.. Choose. Expected color at end point Choose... - Choose... - Choose... - Volume of NaoH used (mL) Average Volume of NaOH used in liters | Average moles of NaOH used (mol) Average moles of acetic acid (mol) Average molarity of acetic acid (M) Average mass of acetic acid (g) Average mass of vinegar (g) (assume the density of vinegar is 1.00 g/mL) ) Average mass % of acetic acid in vinegar Known mass % of acetic acid in vinegar is 5.45%

Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.15 2.05 1.14 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 48.70 48.98 48.36 Choose.. Choose.. Choose. Expected color at end point Choose... - Choose... - Choose... - Volume of NaoH used (mL) Average Volume of NaOH used in liters | Average moles of NaOH used (mol) Average moles of acetic acid (mol) Average molarity of acetic acid (M) Average mass of acetic acid (g) Average mass of vinegar (g) (assume the density of vinegar is 1.00 g/mL) ) Average mass % of acetic acid in vinegar Known mass % of acetic acid in vinegar is 5.45%

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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