I need help with some questions relating to Beer’s Law and solving for concentrations and dilutions. Examples depicted below. Particularly, can you break down the formula (Mcon-Vcon)=(Mdil x Vdil). Thanks! **Pre-Lab Questions: Determining the Concentration of a Solution: Beer's Law**1. How would you prepare 100 mL of 0.4 M CuSO₄ solution? (Include calculation and technique)2. Why does this formula work when diluting solutions? (M₁ × V₁ = M₂ × V₂) Hint: what does M × V equal.3. How many mL of 0.4 M CuSO₄ would you use to make 10 mL of a 0.2 M CuSO₄ solution?4. How many mL of 0.4 M CuSO₄ would you use to make 10 mL of a 0.4 M CuSO₄ solution?5. What is the charge on the copper ion in CuSO₄? Write the electron configuration for that ion.

Given , Volume of CuSO4 we want to prepare V=100 ml Molarity of CuSO4 we want to prepare M=0.4M Molecular mass of CuSO4= =1x 64g+ 1x 32g + 4x16 g = 160g For preparing the solution let is frist calculate the amount of CuSO4 required using the formula of molarity Molartity = (mass / molecular mass) x (1000/volume (in ml) Substituting values 0.4M= (mass/ 160) x (1000/100a) 0.4M = ( mass / 160)× 10 Mass = (0.4 × 160)/10 Mass=6.4g For preparing this solution Weighed out 6 .4 g of Copper sulphate and then added the weighed amount in a standard flask. Then added some water and dissolve the copper sulphate then make the volume to 100 mlWhen we are diluting the solution number of moles before dilution and number of moles after dilution remains the same therefore we use the formula MconcVconc= Mdil Vdil Because molarity is the number of moles of reactant per litre of the solution Of we multiply molarity with volume we get number of moles and number of moles before and after dilution is same3)Given Mconc= 0.4M Vconc=? Mdil=0.04M Vdil=10ml Applying formula MconcVconc=MdilVdil substituting values 0.4M × Vconc= 0.04M ×10ml Vconc= 1ml 4)given Mconc= 0.4M Vconc=? Mdil=0.2M Vdil=10ml Sultituting values in formula used in 3 0.4M×Vconc= 0.2M × 10ml Vconc=5mlCharge on Copper in copper sulphate is +2 The electronic configuration Cu+2 is 1s22s22p63s23p63d9