ns? (Mcon X Vcon) = (Mdil x Vdil) Hint %3D

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Chapter1: Chemical Foundations
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I need help with some questions relating to Beer’s Law and solving for concentrations and dilutions. Examples depicted below. Particularly, can you break down the formula (Mcon-Vcon)=(Mdil x Vdil). Thanks!
**Pre-Lab Questions: Determining the Concentration of a Solution: Beer's Law**

1. How would you prepare 100 mL of 0.4 M CuSO₄ solution? (Include calculation and technique)

2. Why does this formula work when diluting solutions? (M₁ × V₁ = M₂ × V₂) Hint: what does M × V equal.

3. How many mL of 0.4 M CuSO₄ would you use to make 10 mL of a 0.2 M CuSO₄ solution?

4. How many mL of 0.4 M CuSO₄ would you use to make 10 mL of a 0.4 M CuSO₄ solution?

5. What is the charge on the copper ion in CuSO₄? Write the electron configuration for that ion.
Transcribed Image Text:**Pre-Lab Questions: Determining the Concentration of a Solution: Beer's Law** 1. How would you prepare 100 mL of 0.4 M CuSO₄ solution? (Include calculation and technique) 2. Why does this formula work when diluting solutions? (M₁ × V₁ = M₂ × V₂) Hint: what does M × V equal. 3. How many mL of 0.4 M CuSO₄ would you use to make 10 mL of a 0.2 M CuSO₄ solution? 4. How many mL of 0.4 M CuSO₄ would you use to make 10 mL of a 0.4 M CuSO₄ solution? 5. What is the charge on the copper ion in CuSO₄? Write the electron configuration for that ion.
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