Procedure: 1) Preparation of 100 mL 0.1N Na2CO3 2) How much is the molarity of the prepared solution 3) Dilute the solution to get 100 ml 0.01 N. 4) How much the Molarity of the diluted solution. M.wt of Na2CO3 = 106 g mol-1 Eq.wt = 106 / 2 = 53 g eq1 %3D Every 53 g in 1000 ml How much?(x) » in 100 mL → to give 0.1 N 53 x 100 x 0.1 x = 0.53 g 1000 x 1 : weigh 0.53 g Na2CO3 place it in a beaker, add about 30-50 ml distilled water , stir well. Transfer the solution to 100 ml volumetric flask, then fill to the mark with distilled water to get 0.1 N solution. • Put your results and your answers in the following table : Wt. NażCO3 (g) Normality N eq L-1 Molarity M mol L-1 53 ? 0.53 After dilution 0.01

Procedure: 1) Preparation of 100 mL 0.1N Na2CO3 2) How much is the molarity of the prepared solution 3) Dilute the solution to get 100 ml 0.01 N. 4) How much the Molarity of the diluted solution. M.wt of Na2CO3 = 106 g mol-1 Eq.wt = 106 / 2 = 53 g eq1 %3D Every 53 g in 1000 ml How much?(x) » in 100 mL → to give 0.1 N 53 x 100 x 0.1 x = 0.53 g 1000 x 1 : weigh 0.53 g Na2CO3 place it in a beaker, add about 30-50 ml distilled water , stir well. Transfer the solution to 100 ml volumetric flask, then fill to the mark with distilled water to get 0.1 N solution. • Put your results and your answers in the following table : Wt. NażCO3 (g) Normality N eq L-1 Molarity M mol L-1 53 ? 0.53 After dilution 0.01

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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