A 35.0 mL volume of ammonia (NH3) household cleaner needs 53.75 mL of 0.300 M HNO3 to completely neutralize the base. The balanced equation is: HNO3 + NH3 --> NH4NO3 A) Find the number of moles of HNO3 involved in this reaction. (2 hints: start dimensional analysis with the volume of HNO3, & convert mL to L.) B) Find the molarity (M) of the NH3 (This is different than the number of moles. Your calculation will be different from part A.) C) Find the mass/mass % of the NH3. You will need the molar mass of NH3 (17.04 g/mol) & the density of NH3 (0.985 g/mL).

A 35.0 mL volume of ammonia (NH3) household cleaner needs 53.75 mL of 0.300 M HNO3 to completely neutralize the base. The balanced equation is: HNO3 + NH3 --> NH4NO3 A) Find the number of moles of HNO3 involved in this reaction. (2 hints: start dimensional analysis with the volume of HNO3, & convert mL to L.) B) Find the molarity (M) of the NH3 (This is different than the number of moles. Your calculation will be different from part A.) C) Find the mass/mass % of the NH3. You will need the molar mass of NH3 (17.04 g/mol) & the density of NH3 (0.985 g/mL).

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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