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to access important values if needed for this question. Consider the following system at equilibrium where AH° = 111 kJ, and K = 6.30, at 723 K: 2NH3 (9) N₂(g) + 3H₂(g) If the VOLUME on the equilibrium system is suddenly decreased at constant temperature: The value of Ke Oincreases Odecreases Oremains the same The value of Qe O is greater than Ke O is equal to Ke O is less than Kc The reaction must Orun in the forward direction to reestablish equilibrium. Orun in the reverse direction to reestablish equilibrium. Oremain the same. It is already at equilibrium. The number of moles of H₂ will O increase Odecrease Oremain the same Submit Ans Show Hint ry Entire Group 8 more group attempts remaining Previous

to access important values if needed for this question. Consider the following system at equilibrium where AH° = 111 kJ, and K = 6.30, at 723 K: 2NH3 (9) N₂(g) + 3H₂(g) If the VOLUME on the equilibrium system is suddenly decreased at constant temperature: The value of Ke Oincreases Odecreases Oremains the same The value of Qe O is greater than Ke O is equal to Ke O is less than Kc The reaction must Orun in the forward direction to reestablish equilibrium. Orun in the reverse direction to reestablish equilibrium. Oremain the same. It is already at equilibrium. The number of moles of H₂ will O increase Odecrease Oremain the same Submit Ans Show Hint ry Entire Group 8 more group attempts remaining Previous

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Equilibrium System Analysis** Consider the following system at equilibrium where \( \Delta H^° = 111 \, \text{kJ} \), and \( K_c = 6.30 \), at 723 K: \[ 2\text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3\text{H}_2(g) \] If the volume of the equilibrium system is suddenly decreased at constant temperature: 1. **The value of \( K_c \)** - Increases - Decreases - Remains the same 2. **The value of \( Q_c \)** - Is greater than \( K_c \) - Is equal to \( K_c \) - Is less than \( K_c \) 3. **The reaction must** - Run in the forward direction to reestablish equilibrium. - Run in the reverse direction to reestablish equilibrium. - Remain the same. It is already at equilibrium. 4. **The number of moles of \( \text{H}_2 \) will** - Increase - Decrease - Remain the same **Additional Notes:** - **\( K_c \)** (equilibrium constant) depends only on temperature for a given reaction. - **\( Q_c \)** is the reaction quotient, which helps predict the direction in which the reaction will proceed. - Changes in volume affect the concentration of gases and can shift equilibrium according to Le Chatelier's principle.
Transcribed Image Text:**Equilibrium System Analysis** Consider the following system at equilibrium where \( \Delta H^° = 111 \, \text{kJ} \), and \( K_c = 6.30 \), at 723 K: \[ 2\text{NH}_3(g) \rightleftharpoons \text{N}_2(g) + 3\text{H}_2(g) \] If the volume of the equilibrium system is suddenly decreased at constant temperature: 1. **The value of \( K_c \)** - Increases - Decreases - Remains the same 2. **The value of \( Q_c \)** - Is greater than \( K_c \) - Is equal to \( K_c \) - Is less than \( K_c \) 3. **The reaction must** - Run in the forward direction to reestablish equilibrium. - Run in the reverse direction to reestablish equilibrium. - Remain the same. It is already at equilibrium. 4. **The number of moles of \( \text{H}_2 \) will** - Increase - Decrease - Remain the same **Additional Notes:** - **\( K_c \)** (equilibrium constant) depends only on temperature for a given reaction. - **\( Q_c \)** is the reaction quotient, which helps predict the direction in which the reaction will proceed. - Changes in volume affect the concentration of gases and can shift equilibrium according to Le Chatelier's principle.
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If the volume of a gaseous reaction is decreased, the pressure exerted by the molecules will increase. Thus, the effect of decrease of volume is equivalent to the effect of increase of pressure. 

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