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ot Given the following equilibrium constants at 427°C, Na2O(s) = 2 Na(l) + O2(9) K₁ = 6 × 10-25 t NaO(g) = Na(l) + O2(g) K2 = 2 x 10-5 Na2O2 (s) 2 Na(!) + O2(g) K3 = 7 x 10-29 NaO2(s) Na(l) + O2(g) K₁ = 1 x 10-14 t [ determine the values for the equilibrium constants for the following reactions: a. Na₂O(s) + 02 (9) Na2O2 (s) Equilibrium constant = b. NaO(g) + Na2O(s) Na2O2 (s) + Na(!) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

ot Given the following equilibrium constants at 427°C, Na2O(s) = 2 Na(l) + O2(9) K₁ = 6 × 10-25 t NaO(g) = Na(l) + O2(g) K2 = 2 x 10-5 Na2O2 (s) 2 Na(!) + O2(g) K3 = 7 x 10-29 NaO2(s) Na(l) + O2(g) K₁ = 1 x 10-14 t [ determine the values for the equilibrium constants for the following reactions: a. Na₂O(s) + 02 (9) Na2O2 (s) Equilibrium constant = b. NaO(g) + Na2O(s) Na2O2 (s) + Na(!) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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ot Given the following equilibrium constants at 427°C, Na2O(s) = 2 Na(l) + O2(9) K₁ = 6 × 10-25 t NaO(g) = Na(l) + O2(g) K2 = 2 x 10-5 Na2O2 (s) 2 Na(!) + O2(g) K3 = 7 x 10-29 NaO2(s) Na(l) + O2(g) K₁ = 1 x 10-14 t [ determine the values for the equilibrium constants for the following reactions: a. Na₂O(s) + 02 (9) Na2O2 (s) Equilibrium constant = b. NaO(g) + Na2O(s) Na2O2 (s) + Na(!) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)
Transcribed Image Text:ot Given the following equilibrium constants at 427°C, Na2O(s) = 2 Na(l) + O2(9) K₁ = 6 × 10-25 t NaO(g) = Na(l) + O2(g) K2 = 2 x 10-5 Na2O2 (s) 2 Na(!) + O2(g) K3 = 7 x 10-29 NaO2(s) Na(l) + O2(g) K₁ = 1 x 10-14 t [ determine the values for the equilibrium constants for the following reactions: a. Na₂O(s) + 02 (9) Na2O2 (s) Equilibrium constant = b. NaO(g) + Na2O(s) Na2O2 (s) + Na(!) Equilibrium constant = c. 2 NaO(g) Na2O2 (s) Equilibrium constant = (Hint: When reaction equations are added, the equilibrium expressions are multiplied.)
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