Consider the equilibrium system described by the chemical reaction below. If 0.1908 moles of CO2, 0.0908 moles of H₂, 0.0092 moles of CO, and 0.0092 moles of H₂O are present in a 2.00 L reaction vessel at equilibrium at 300 K, what is the value of Kc of the reaction at this temperature? CO₂(g) + H₂(g) = CO(g) + H₂O(g) 1 Based on the given data, set up the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. Once the expression is constructed, solve for Kc. Kc = 11

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9:10
Consider the equilibrium system described by
the chemical reaction below. If 0.1908 moles of
CO2, 0.0908 moles of H₂, 0.0092 moles of CO,
and 0.0092 moles of H₂O are present in a 2.00 L
reaction vessel at equilibrium at 300 K, what is
the value of Kc of the reaction at this
temperature?
Question 5 of 10
CO₂(g) + H₂(g) = CO(g) + H₂O(g)
1
Based on the given data, set up the expression
for Kc. Each reaction participant must be
represented by one tile. Do not combine terms.
Kc =
Once the expression is constructed, solve for
Kc.
[0.1908]
[0.0092]
[0.0908]²
[0.0092]²
1.1
Submit
[0.0908]
[0.0184]
[2.00]
[0.0184]²
=
[0.0954]
[0.0046]
[300]
200
Tap here or pull up for additional resources
RESET
[0.0454]
[0.1908]²
[0.0954]²
4.9 × 10-³
Transcribed Image Text:9:10 Consider the equilibrium system described by the chemical reaction below. If 0.1908 moles of CO2, 0.0908 moles of H₂, 0.0092 moles of CO, and 0.0092 moles of H₂O are present in a 2.00 L reaction vessel at equilibrium at 300 K, what is the value of Kc of the reaction at this temperature? Question 5 of 10 CO₂(g) + H₂(g) = CO(g) + H₂O(g) 1 Based on the given data, set up the expression for Kc. Each reaction participant must be represented by one tile. Do not combine terms. Kc = Once the expression is constructed, solve for Kc. [0.1908] [0.0092] [0.0908]² [0.0092]² 1.1 Submit [0.0908] [0.0184] [2.00] [0.0184]² = [0.0954] [0.0046] [300] 200 Tap here or pull up for additional resources RESET [0.0454] [0.1908]² [0.0954]² 4.9 × 10-³
Expert Solution
Step 1

Well, we have to calculate the equilibrium concentration as only moles at equilibrium is only given-

Concentration=Number of molesTotal volume in L

for a reaction-

aA+bBcC+dD

the equilibrium constant-

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