For which of these reactions will there be no effect on the relative amounts of the substances present at equilibrium when the pressure of the system is increased at constant temperature? O 2 s0,(g) + 0,(g) =250,(g) + heat heat + CO,(g) + NOg) =COg) + NO,(g) heat + 2Cl,(g) + 2H,0(g) =4 HCI(g) + 0,(g) O N, (g) + 3 H, (g) =2 NH,(g) + heat

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### Impact of Pressure on Chemical Equilibrium

In this section, we explore how changes in pressure affect the relative amounts of substances present at equilibrium for various chemical reactions. Consider the provided reactions and determine which one is unaffected by an increase in pressure at constant temperature.

1. **Reaction 1:**
   \[
   2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) + \text{heat}
   \]

2. **Reaction 2:**
   \[
   \text{heat} + CO_2(g) + NO(g) \rightleftharpoons CO(g) + NO_2(g)
   \]

3. **Reaction 3:**
   \[
   \text{heat} + 2C_l2(g) + 2H_2O(g) \rightleftharpoons 4HCl(g) + O_2(g)
   \]

4. **Reaction 4:**
   \[
   N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + \text{heat}
   \]

### Explanation:

- **Reaction 1**: \(2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) + \text{heat}\)
  - **Analysis**: Increasing pressure favors the side with fewer gas molecules. Here, 3 moles of reactants (gases) form 2 moles of products (gases). Thus, the equilibrium will shift to the right.

- **Reaction 2**: \(\text{heat} + CO_2(g) + NO(g) \rightleftharpoons CO(g) + NO_2(g)\)
  - **Analysis**: This reaction involves 2 moles of reactants (gases) and forms 2 moles of products (gases). Thus, increasing pressure will have no effect on the equilibrium position.

- **Reaction 3**: \(\text{heat} + 2Cl_2(g) + 2H_2O(g) \rightleftharpoons 4HCl(g) + O_2(g)\)
  - **Analysis**: Here, 4 moles of reactants (gases) form 5 moles of products (g
Transcribed Image Text:### Impact of Pressure on Chemical Equilibrium In this section, we explore how changes in pressure affect the relative amounts of substances present at equilibrium for various chemical reactions. Consider the provided reactions and determine which one is unaffected by an increase in pressure at constant temperature. 1. **Reaction 1:** \[ 2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) + \text{heat} \] 2. **Reaction 2:** \[ \text{heat} + CO_2(g) + NO(g) \rightleftharpoons CO(g) + NO_2(g) \] 3. **Reaction 3:** \[ \text{heat} + 2C_l2(g) + 2H_2O(g) \rightleftharpoons 4HCl(g) + O_2(g) \] 4. **Reaction 4:** \[ N_2(g) + 3H_2(g) \rightleftharpoons 2NH_3(g) + \text{heat} \] ### Explanation: - **Reaction 1**: \(2SO_2(g) + O_2(g) \rightleftharpoons 2SO_3(g) + \text{heat}\) - **Analysis**: Increasing pressure favors the side with fewer gas molecules. Here, 3 moles of reactants (gases) form 2 moles of products (gases). Thus, the equilibrium will shift to the right. - **Reaction 2**: \(\text{heat} + CO_2(g) + NO(g) \rightleftharpoons CO(g) + NO_2(g)\) - **Analysis**: This reaction involves 2 moles of reactants (gases) and forms 2 moles of products (gases). Thus, increasing pressure will have no effect on the equilibrium position. - **Reaction 3**: \(\text{heat} + 2Cl_2(g) + 2H_2O(g) \rightleftharpoons 4HCl(g) + O_2(g)\) - **Analysis**: Here, 4 moles of reactants (gases) form 5 moles of products (g
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