Consider the equilibrium system described by the chemical reaction below. At equilibrium, a 5.0 L reaction vessel contained a mixture of 1.2 mol CH4, 2.8 mol H₂S, 0.63 mol CS2, and 0.042 mol H₂ at 93.0 °C. What are the values of Kc and Kp for the reaction at this temperature? Complete Parts 1-2 before submitting your answer. CH₂(g) + 2 H₂S(g) = CS₂(s) + 4 H₂(g) 1 2
Consider the equilibrium system described by the chemical reaction below. At equilibrium, a 5.0 L reaction vessel contained a mixture of 1.2 mol CH4, 2.8 mol H₂S, 0.63 mol CS2, and 0.042 mol H₂ at 93.0 °C. What are the values of Kc and Kp for the reaction at this temperature? Complete Parts 1-2 before submitting your answer. CH₂(g) + 2 H₂S(g) = CS₂(s) + 4 H₂(g) 1 2
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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
Transcribed Image Text:9:58
Consider the equilibrium system described by
the chemical reaction below. At equilibrium, a
5.0 L reaction vessel contained a mixture of 1.2
mol CH4, 2.8 mol H₂S, 0.63 mol CS2, and 0.042
mol H₂ at 93.0 °C. What are the values of Kc
and Kp for the reaction at this temperature?
Complete Parts 1-2 before submitting your
answer.
Question 10 of 10
CH₂(g) + 2 H₂S(g) = CS₂(s) + 4H₂(g)
1
0.063
2
Based on your value of Kc, determine the value
of Kp under these conditions.
Kp =
3.8 x 10-6
1.1 x 10-⁹
16
6.0 x 10-5
Submit
6.6 x 10-8
7.3 x 10-¹¹
Tap here or pull up for additional resources
RESET
1.5 x 10²
2.0 x 10-6
![9:58
Question 10 of 10
Consider the equilibrium system described by
the chemical reaction below. At equilibrium, a
5.0 L reaction vessel contained a mixture of 1.2
mol CH4, 2.8 mol H₂S, 0.63 mol CS2, and 0.042
mol H₂ at 93.0 °C. What are the values of Kc
and Kp for the reaction at this temperature?
Complete Parts 1-2 before submitting your
answer.
CH₂(g) + 2 H₂S(g) = CS₂(s) + 4H₂(g)
1
2
Based on the given data, set up the expression
for Kc. Each reaction participant must be
represented by one tile. Do not combine terms.
Kc =
Once the expression is constructed, solve for
Kc.
[1.2]
[0.24]
2[2.8]
4[0.042]
0.063
Submit
[2.8]
[0.56]
[2.8]²
[0.042]4
16
=
[0.63]
[0.13]
2[0.56]
4[0.0084]
6.6 x 10-8
Tap here or pull up for additional resources
RESET
[0.042]
[0.0084]
[0.56]²
[0.0084]¹
1.5 x 10²](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8b570b0f-6e1b-46f1-92cb-002d89189618%2F03c42098-ce90-48c2-9570-d74e14a1bb58%2Fp9kboza_processed.jpeg&w=3840&q=75)
Transcribed Image Text:9:58
Question 10 of 10
Consider the equilibrium system described by
the chemical reaction below. At equilibrium, a
5.0 L reaction vessel contained a mixture of 1.2
mol CH4, 2.8 mol H₂S, 0.63 mol CS2, and 0.042
mol H₂ at 93.0 °C. What are the values of Kc
and Kp for the reaction at this temperature?
Complete Parts 1-2 before submitting your
answer.
CH₂(g) + 2 H₂S(g) = CS₂(s) + 4H₂(g)
1
2
Based on the given data, set up the expression
for Kc. Each reaction participant must be
represented by one tile. Do not combine terms.
Kc =
Once the expression is constructed, solve for
Kc.
[1.2]
[0.24]
2[2.8]
4[0.042]
0.063
Submit
[2.8]
[0.56]
[2.8]²
[0.042]4
16
=
[0.63]
[0.13]
2[0.56]
4[0.0084]
6.6 x 10-8
Tap here or pull up for additional resources
RESET
[0.042]
[0.0084]
[0.56]²
[0.0084]¹
1.5 x 10²
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