H₂S and O₂ react according to the equation below. The reaction between H₂S and O₂ has a value Kp equal to 4.7 x 10-10 at 200 K. Predict the equilibrium pressure of SO₂ by constructing an ICE table, writing the equilibrium constant expression expressed in terms of partial pressure, and solving for the equilibrium partial pressure of SO₂. Complete Parts 1-3 before submitting your answer. 2 H₂S(g) + 3 O₂(g) = 2 H₂O(g) + 2 SO₂(g) PREV NEXT > Using the data from your ICE Table construct the expression for the equilibrium constant, Kp. Each reaction participant must be represented by one tile. Do not combine terms. 1 Kp = 11 3 = 4.7 x 10-1⁰
H₂S and O₂ react according to the equation below. The reaction between H₂S and O₂ has a value Kp equal to 4.7 x 10-10 at 200 K. Predict the equilibrium pressure of SO₂ by constructing an ICE table, writing the equilibrium constant expression expressed in terms of partial pressure, and solving for the equilibrium partial pressure of SO₂. Complete Parts 1-3 before submitting your answer. 2 H₂S(g) + 3 O₂(g) = 2 H₂O(g) + 2 SO₂(g) PREV NEXT > Using the data from your ICE Table construct the expression for the equilibrium constant, Kp. Each reaction participant must be represented by one tile. Do not combine terms. 1 Kp = 11 3 = 4.7 x 10-1⁰
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![H₂S and O₂ react according to the equation below. The reaction between H₂S and O₂ has
a value Kp equal to 4.7 x 10-10 at 200 K. Predict the equilibrium pressure of SO₂ by
constructing an ICE table, writing the equilibrium constant expression expressed in terms
of partial pressure, and solving for the equilibrium partial pressure of SO2. Complete Parts
1-3 before submitting your answer.
2 H₂S(g) + 3 O₂(g) = 2 H₂O(g) + 2 SO₂(g)
PREV
(2.00-2x)
(5.00 - 2x)
(x)²
Using the data from your ICE Table construct the expression for the equilibrium constant, Kp. Each reaction
participant must be represented by one tile. Do not combine terms.
(2.00 + 2x)
1
(5.00 + 2x)²
Кр
(2x)
Question 23 of 26
(2.00-2.x)²
(5.00 -3.x)³
(2x)²
(2.00 +2.x)²
(5.00 + 3x)³
(2.00-x)
(5.00-x)
3
= 4.7 x 10-1⁰
(2.00 + x)
(5.00 + x)
(2.00- x)²
NEXT
(5.00-x)³
RESET
(2.00 + x)²
(5.00 + x)³](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19cce641-b997-49dc-afd2-8bab9dcfc62b%2F636c310c-ba55-4b42-b845-dad31dcf0363%2Fjjvrz6c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:H₂S and O₂ react according to the equation below. The reaction between H₂S and O₂ has
a value Kp equal to 4.7 x 10-10 at 200 K. Predict the equilibrium pressure of SO₂ by
constructing an ICE table, writing the equilibrium constant expression expressed in terms
of partial pressure, and solving for the equilibrium partial pressure of SO2. Complete Parts
1-3 before submitting your answer.
2 H₂S(g) + 3 O₂(g) = 2 H₂O(g) + 2 SO₂(g)
PREV
(2.00-2x)
(5.00 - 2x)
(x)²
Using the data from your ICE Table construct the expression for the equilibrium constant, Kp. Each reaction
participant must be represented by one tile. Do not combine terms.
(2.00 + 2x)
1
(5.00 + 2x)²
Кр
(2x)
Question 23 of 26
(2.00-2.x)²
(5.00 -3.x)³
(2x)²
(2.00 +2.x)²
(5.00 + 3x)³
(2.00-x)
(5.00-x)
3
= 4.7 x 10-1⁰
(2.00 + x)
(5.00 + x)
(2.00- x)²
NEXT
(5.00-x)³
RESET
(2.00 + x)²
(5.00 + x)³
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