A student ran the following reaction in the laboratory at 480 K: PCI 5(9) =PC13(g) + Cl₂(g) When he introduced PCI 5(g) at a pressure of 0.567 atm into a 1.00 L evacuated container, he found the equilibrium partial pressure of Cl₂(g) to be 0.254 atm. Calculate the equilibrium constant, Kp, he obtained for this reaction. Kp =

Chemistry: The Molecular Science
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Chapter19: The Chemistry Of The Main-group Elements
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A student ran the following reaction in the laboratory at 480 K:
PCI5(g) =PC13(g) +
When he introduced PCI5(g) at a pressure of 0.567 atm into a 1.00 L evacuated container, he found the equilibrium partial pressure of Cl₂(g) to be 0.254 atm.
Calculate the equilibrium constant, Kp, he obtained for this reaction.
Kp
=
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Cl₂(g)
Retry Entire Group 8 more group attempts remaining
Transcribed Image Text:A student ran the following reaction in the laboratory at 480 K: PCI5(g) =PC13(g) + When he introduced PCI5(g) at a pressure of 0.567 atm into a 1.00 L evacuated container, he found the equilibrium partial pressure of Cl₂(g) to be 0.254 atm. Calculate the equilibrium constant, Kp, he obtained for this reaction. Kp = Submit Answer Cl₂(g) Retry Entire Group 8 more group attempts remaining
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