A student ran the following reaction in the laboratory at 312 K: 2CH₂Cl₂(g) →CH4(g) + CCl4(g) When he introduced CH₂Cl₂(g) at a pressure of 0.484 atm into a 1.00 L evacuated container, he found the equilibrium partial pressure of CCl4(g) to be 0.219 atm. Calculate the equilibrium constant, Kp, he obtained for this reaction. Кр

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Chapter12: Chemical Equilibrium
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Problem 41QRT: Nitrosyl chloride, NOC1, decomposes to NO and Cl2 at high temperatures. 2 NOCl(g) ⇌ 2 NO(g) +...
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A student ran the following reaction in the laboratory at 312 K:
2CH₂Cl₂(g) CH4(g) + CCl4(g)
When he introduced CH₂Cl₂(g) at a pressure of 0.484 atm into a 1.00 L evacuated container, he found the
equilibrium partial pressure of CCl4(g) to be 0.219 atm.
Calculate the equilibrium constant, Kp, he obtained for this reaction.
Kp =
Transcribed Image Text:A student ran the following reaction in the laboratory at 312 K: 2CH₂Cl₂(g) CH4(g) + CCl4(g) When he introduced CH₂Cl₂(g) at a pressure of 0.484 atm into a 1.00 L evacuated container, he found the equilibrium partial pressure of CCl4(g) to be 0.219 atm. Calculate the equilibrium constant, Kp, he obtained for this reaction. Kp =
Write the equilibrium constant expression, Kc, for the following reaction:
(If either the numerator or denominator is 1, please enter 1.)
Kc
=
2-
Ba²+ (aq) + SO3²- (aq) ⇒ BaSO3 (s)
Transcribed Image Text:Write the equilibrium constant expression, Kc, for the following reaction: (If either the numerator or denominator is 1, please enter 1.) Kc = 2- Ba²+ (aq) + SO3²- (aq) ⇒ BaSO3 (s)
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