to accelerate at
Q: What is the magnitude of the electric field at the point (2.60 i -6.20j+ 2.20 k) m if the electric…
A: Position given = 2.6i^ - 6.2j^ +2.2k^ V (Potential) = 1.5xyz2 E = -(gradient of V)
Q: Need c only tq !
A:
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A:
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A: Given, F=30 Nθ=400m=30 kgd=7.2 m
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A: the wavelength of light=618nm Two adjacent maxima occur at sinθ=0.24 & sinθ=0.35
Q: Two 3D vectors are given d = 4i – 3j + 1k 3 =-li + lj + 4k Find (a) 글 + 7 (b) 값-ㅎ (c) if R-27 +37 =…
A: a. a→+b→=4i^-3j^+1k^+-1i^+1j^+4k^=3i^-2j^+5k^
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A: We have given Diameter d = 0.20 cm Radius r = d/2 r = 0.20/2= 0.10 cm r =…
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A: Given: K1 = 3.9 K2 =3.2 K3 = 4.2 a = 33 mm = 0.033 m d = 43 mm = 0.043 m A = 46 cm2 = 0.0046 m2
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Q: Can you please answer def as a followup if thats allowed?
A:
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A: by using this value we can proceed to solve this
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Q: Two charges are situated near point P. q₁ = 0.025 µC and q2 = 0.12 µC. Find the electric field…
A: Given: In this question, the given details are, Here, the two charges are situated near point P ,…
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A: Here, we have to calculate the electric field.
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A: 1st question solution:
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A:
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