Answered: tn charge? W (d) 21, A particle with…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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I am having a hard time understanding why the solved answer on your site, for the following question, uses x-2 instead of x+2 for the -2q charge. I attached my work for part A as well as where I am confused at. Aren't I just supposed to solve for x at this point? The - seems to be throwing me off. Any explanation you can offer would be appreciated!

tn
charge?
W (d)
21, A particle with charge +q is at the origin. A particle with
Se
charge -2q is at x = 2.00 m on the x axis. (a) For what finite
to
value (s) of x is the electric field zero? (b) For what finite
value (s) of x is the electric potential zero?
30
bail ()

Expert Solution

Step 1

Given $q_{1} = + q a t o r i g i n q_{1} = - 2 q d i s \tan e b e t w e e n t h e m i s r = 2.0 m$

From Coulomb's law, we know the electric field at a distance r form the point is given as

$|\vec{E}| = k_{e} \frac{|q|}{r^{2}} k_{e} = \frac{1}{4 {πε}_{\circ}} = 9 \times 10^{9} N m^{2} / C^{2}$

And electric potential at some point due to several point charge is the sum of individual potential

$V = \sum_{i} V_{i} = k_{e} \sum_{i} \frac{q_{i}}{r_{i}}$

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