Consider a rod of length I carrying a charge of q distributed uniformly over its length. L- Where applicable, let V(r → ∞) = 0. Hint Vp= q = a. What is the voltage V at point P (at distance a away from the near end of the rod) due to the charge over the length of the rod? Express your answer in terms of given parameters (L,q,a) and physical constants (ke, Eo). Use underscore ("_") for subscripts and spell out Greek letters. Hint for (a) E = a P b. Calculate the electric field at point P by differentiating V with respect to a. Let positive sign of E indicate direction of electric field pointing away from the rod. Hint for (b) Question Help: Message instructor

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Consider a rod of length L carrying a charge of q distributed uniformly over its length.
Where applicable, let V(r → ∞) = 0.
Hint
q
a. What is the voltage V at point P (at distance a away from the near end of the rod) due to the
charge over the length of the rod? Express your answer in terms of given parameters (L,q,a) and
physical constants (ke, Eo). Use underscore ("_") for subscripts and spell out Greek letters.
Hint for (a)
E =
Vp =
b. Calculate the electric field at point P by differentiating V with respect to a. Let positive sign of E
indicate direction of electric field pointing away from the rod.
Hint for (b)
a
Question Help: Message instructor
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Transcribed Image Text:Consider a rod of length L carrying a charge of q distributed uniformly over its length. Where applicable, let V(r → ∞) = 0. Hint q a. What is the voltage V at point P (at distance a away from the near end of the rod) due to the charge over the length of the rod? Express your answer in terms of given parameters (L,q,a) and physical constants (ke, Eo). Use underscore ("_") for subscripts and spell out Greek letters. Hint for (a) E = Vp = b. Calculate the electric field at point P by differentiating V with respect to a. Let positive sign of E indicate direction of electric field pointing away from the rod. Hint for (b) a Question Help: Message instructor Submit Question с MacBook Pro G Search or type URL ☆ +
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