Titration lab: NaOH +HCl->NaCl+H2O • Watch the video : htps:/www.youtube.com/watch?v=cdvkZCNhvf4 • Initial volume of NaOH in the burete= 0.90ml • Final volume of NaOH in the burete=30.90 • Volume of NaOH= final volume-initial volume=30.0 ml NaOH • M NAOH= 0.10M > 0. ImolL. NaOH • FIRST TITRATION=is to find the exact Mof N2OH WE Call the first experiment= standardization of base • We found out the Mof base =0.10 M • Volume of HCl in the flask= 10.00 ml they grabbed it with pipet glassware. Pipette is reaaly precise even more than graduated cylinder we should go upto two after decimal point. • M of HC? Chapter 7 flash back 30.0ml N2OHX IL NAOH x 0.10molNaOH xImol HCI = 0.003mol HCI 1000ml NaOH IL NaOH Imol NaOH Find M of HCI?

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Titration lab: NaOH +HCl-> NaCl+H2O
• Watch the video : https://www.youtube.com/watch?v=cdvkZCNhvf4
Initial volume of NaOH in the burete= 0.90ml
• Final volume of NAOH in the burete=30.90
• Volume of NaOH= final volume-initial volume=30.0 ml NAOH
• M NAOH= 0.10M -> 0. ImolL. NaOH
• FIRST TITRATION= is to find the exact M of NaOH WE Call the first experiment= standardization of base
We found out the M of base =0.10 M
• Volume of HCl in the flask= 10.00 ml they grabbed it with pipet glassware. Pipette is reaaly precise even more than graduated cylinder we should go upto two after decimal point.
M of HCI? Chapter 7 flash back
30.0ml NaOHX IL NAOH x_0.10molNaOH xlmol HCI = 0.003mol HCI
1000ml NaOH IL NAOH
Imol NaOH
Find M of HCI?
Transcribed Image Text:Titration lab: NaOH +HCl-> NaCl+H2O • Watch the video : https://www.youtube.com/watch?v=cdvkZCNhvf4 Initial volume of NaOH in the burete= 0.90ml • Final volume of NAOH in the burete=30.90 • Volume of NaOH= final volume-initial volume=30.0 ml NAOH • M NAOH= 0.10M -> 0. ImolL. NaOH • FIRST TITRATION= is to find the exact M of NaOH WE Call the first experiment= standardization of base We found out the M of base =0.10 M • Volume of HCl in the flask= 10.00 ml they grabbed it with pipet glassware. Pipette is reaaly precise even more than graduated cylinder we should go upto two after decimal point. M of HCI? Chapter 7 flash back 30.0ml NaOHX IL NAOH x_0.10molNaOH xlmol HCI = 0.003mol HCI 1000ml NaOH IL NAOH Imol NaOH Find M of HCI?
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