Titration Part Molarity HCI Initial Buret Final Buret Volume of HCI Reading Reading Trial 1 6 M 0.0ml 7.55ml 7.55ml Trial 2 6 M 0.0ml 7.6ml 7.6ml 4. Calculate the number of moles of OH formed. (Must show calculation for each trial.)

Titration Part Molarity HCI Initial Buret Final Buret Volume of HCI Reading Reading Trial 1 6 M 0.0ml 7.55ml 7.55ml Trial 2 6 M 0.0ml 7.6ml 7.6ml 4. Calculate the number of moles of OH formed. (Must show calculation for each trial.)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Titration Part
Molarity HCI
Initial Buret
Final Buret
Volume of HCI
Reading
Reading
6 M
6 M
Trial 1
0.0mL
7.55mL
7.55ml
Trial 2
0.0mL
7.6mL
7.6ml
4.
Calculate the number of moles of OH formed. (Must show calculation for each trial.)
5.
Determine the ratio of moles of OH / moles of Ca2+. (Must show your calculation for each
trial.)

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10. How many mililiters of 0.085 M NaOH are required to titrate the following solution to the equivalence point: 40.0 mL of 0.0900M HNO3 Group of answer choices A) 42.4 mL NaOH soln B) 23.6 mL C.) 37.8 mL D.) 40.0 mL
Solve only D ... Don't provide handwriting solutions....
Please give me correct solution.
all 3 parts please