Table 2 Determination of the K, of an Unknown Weak Acid.Number of unknown acid:Trial #1Trial #21. Volume of base added to reach equivalence pointmLmL2. Volume of base added at the half-equivalence pointmLmL3. pH at the half-equivalence point4. pK,5. KCalculations (see Introduction):Average K,: Table 1 Titration Data.Trial #1Trial #1 (continued)Trial #2Trial #2 (continued)Volume ofVolume ofNAOH added(mL)Volume ofVolume ofNAOH added(mL)pHNAOH addedpHpHNaOH addedpH(mL)(mL)4.30 Iml4.514.444,954..304.524.984.95S.155.300.000.002.2.3.5.28S.S2$,505.505.90S.80S, 86.046.2016.50T.1610.10 7.610.20 8.321U.308.780.40 9.2810.509.57A0.211.08So64S,g66.076.644.58.08.31612a.s1012141694.62

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Answered: 1. Volume of base added to reach…

1. Volume of base added to reach equivalence point 2. Volume of base added at the half-equivalence point 3. pH at the half-equivalence point 4. pK 5. K

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Table 2 Determination of the K, of an Unknown Weak Acid.
Number of unknown acid:
Trial #1
Trial #2
1. Volume of base added to reach equivalence point
mL
mL
2. Volume of base added at the half-equivalence point
mL
mL
3. pH at the half-equivalence point
4. pK,
5. K
Calculations (see Introduction):
Average K,:

Table 1 Titration Data.
Trial #1
Trial #1 (continued)
Trial #2
Trial #2 (continued)
Volume of
Volume of
NAOH added
(mL)
Volume of
Volume of
NAOH added
(mL)
pH
NAOH added
pH
pH
NaOH added
pH
(mL)
(mL)
4.30 Iml
4.51
4.44
4,95
4..30
4.52
4.98
4.95
S.15
5.30
0.00
0.00
2.
2.
3.
5.28
S.S2
$,505.50
5.90
S.80
S, 8
6.04
6.20
16.50
T.16
10.10 7.6
10.20 8.32
1U.308.78
0.40 9.28
10.509.57
A0.21
1.08
So64
S,g6
6.07
6.64
4.5
8.0
8.3
16
12
a.s
10
12
14
169
4.62

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