How many grams of dry NHạ Cl need to be added to 2.00 L of a 0.100 M solution of ammonia, NHa, to prepare a buffer solution that has a pH of 8.98? K for ammonia is 1.8 x 10 Express your answer with the appropriate units.

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help with part b please
V.E. CHEM 02 Spring 2021
Course Home
<Ch 18 Part 1 Buffers, Titrations, Solubility
Question 4
Just as pH is the negative logarithm of
H,O+1. pK, is the negative logarithm of
K..
- Part A
pK =-log K,
Acetic acid has a K, of 1.8 x 10-5. Three acetic acid/acetate buffer solutions, A B, and C, were made using varying concentrations:
The Henderson-Hasselbalch equation is used to
calculate the pH of buffer solutions:
A [acetic acid] ten times greater than (acetate).
B. acetate ten times greater than [acetic acid), and
c. Jacetate = [acetic acid].
base)
pH = pK, +log
scid)
Match each buffer to the expected pH.
Notice that the pH of a buffer has a value
close to the pK, of the acid, differing only by
the logarithm of the concentration ratio
(basel/lacád). The Henderson-Hasselbalch
equation in tems of pOH and pK is similar.
Drag the appropriate items to their respective bins.
> View Available Hint(s)
Reset Help
POH = pK +log
%3D
base)
pH = 3.74
pH= 4.74
PH = 5.74
(acicadd) len Imer
geaer han (aa e
(atae) en Imes
pmaer han slc
add)
Case)- (azicadd)
Pre viou Anri
v Correct
earch
Transcribed Image Text:V.E. CHEM 02 Spring 2021 Course Home <Ch 18 Part 1 Buffers, Titrations, Solubility Question 4 Just as pH is the negative logarithm of H,O+1. pK, is the negative logarithm of K.. - Part A pK =-log K, Acetic acid has a K, of 1.8 x 10-5. Three acetic acid/acetate buffer solutions, A B, and C, were made using varying concentrations: The Henderson-Hasselbalch equation is used to calculate the pH of buffer solutions: A [acetic acid] ten times greater than (acetate). B. acetate ten times greater than [acetic acid), and c. Jacetate = [acetic acid]. base) pH = pK, +log scid) Match each buffer to the expected pH. Notice that the pH of a buffer has a value close to the pK, of the acid, differing only by the logarithm of the concentration ratio (basel/lacád). The Henderson-Hasselbalch equation in tems of pOH and pK is similar. Drag the appropriate items to their respective bins. > View Available Hint(s) Reset Help POH = pK +log %3D base) pH = 3.74 pH= 4.74 PH = 5.74 (acicadd) len Imer geaer han (aa e (atae) en Imes pmaer han slc add) Case)- (azicadd) Pre viou Anri v Correct earch
grealer han (azlc
OH and pK is similar
6 +log eid)
|base)
Submit
Pre vlouI Aners
v Correct
Part B
How many grams of dry NH4 Cl need to be added to 2.00 L of a 0.100 M solution of ammonia, NH3, to prepare a buffer solution that has a pH of 8.98? K, for ammonia is 1.8 x 10-
Express your answer with the appropriate units.
> View Available Hint(s)
O IE
mass of NH4 C1 = 43.16
Submit
Pre vlou An ri
X Incorrect; Try Again; 6 attempts remaining
Ne
Provide Feedback
P Pearson
CopyrightO 2021 Pearson Education Inc. All rights reserved. Ternms of Use I PrivacX Poliey I Permissions I Contact Us I
00:6
A 4) G
4/19/
hp
近
Transcribed Image Text:grealer han (azlc OH and pK is similar 6 +log eid) |base) Submit Pre vlouI Aners v Correct Part B How many grams of dry NH4 Cl need to be added to 2.00 L of a 0.100 M solution of ammonia, NH3, to prepare a buffer solution that has a pH of 8.98? K, for ammonia is 1.8 x 10- Express your answer with the appropriate units. > View Available Hint(s) O IE mass of NH4 C1 = 43.16 Submit Pre vlou An ri X Incorrect; Try Again; 6 attempts remaining Ne Provide Feedback P Pearson CopyrightO 2021 Pearson Education Inc. All rights reserved. Ternms of Use I PrivacX Poliey I Permissions I Contact Us I 00:6 A 4) G 4/19/ hp 近
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