The velocity of a 30-kg object is given by v = 3t2i – (6t + 5t3)i, where if t is in seconds, then v will be in meters per second. (a) What is the net force on the object as a function of time? (Assume SI units. Do not include units in your answer.) Frot î + %3D (b) What is the momentum of the object when t = 13.0 s? (Express your answer in vector form.) kg • m/s

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Chapter1: Units, Trigonometry. And Vectors
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The velocity of a 30-kg object is given by v = 3t2i - (6t +
5t3)j, where if t is in seconds, then v will be in meters per second.
(a) What is the net force on the object as a function of time? (Assume SI units. Do not include units in your answer.)
Ftot
%3D
(b) What is the momentum of the object when t = 13.0 s? (Express your answer in vector form.)
kg · m/s
%3D
Transcribed Image Text:The velocity of a 30-kg object is given by v = 3t2i - (6t + 5t3)j, where if t is in seconds, then v will be in meters per second. (a) What is the net force on the object as a function of time? (Assume SI units. Do not include units in your answer.) Ftot %3D (b) What is the momentum of the object when t = 13.0 s? (Express your answer in vector form.) kg · m/s %3D
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