6.3 PQ equal to the rate of change of momentum, F = d(mv)/ dt. Tak- ing the derivative by parts yields F = m(dv) / (dt) + v(dm) / (dt). This does not correspond to F = ma. What is the source 1 Newton's second law can be stated that the force is %3D

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Chapter1: Units, Trigonometry. And Vectors
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6.3 PQ1 Newton's second law can be stated that the force is
equal to the rate of change of momentum, F = d(mv)/dt. Tak-
ing the derivative by parts yields F = m(dv) / (dt) + v(dm) /
(dt). This does not correspond to F = ma. What is the source
of the discrepancy?
%3D
Transcribed Image Text:6.3 PQ1 Newton's second law can be stated that the force is equal to the rate of change of momentum, F = d(mv)/dt. Tak- ing the derivative by parts yields F = m(dv) / (dt) + v(dm) / (dt). This does not correspond to F = ma. What is the source of the discrepancy? %3D
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