dxa"+m+Pexp(-2ax²). %3D 1. Explain in your own words what the terminology for each of the quantities in above expression is. 2. When k=n+m+p is an odd number, what can you say about the integral?
dxa"+m+Pexp(-2ax²). %3D 1. Explain in your own words what the terminology for each of the quantities in above expression is. 2. When k=n+m+p is an odd number, what can you say about the integral?
Related questions
Question
2. Please answer the question completely and accurately with full detailed steps.
![dro,(x)x® Óm(x) =| d
If we have trial functions, which depend on n, of the form ø,n = x"exp(-ax). We are
interested in being able to perform integrals (for any values of n, m and p) of the form:
+oo
dxr"+m+Pexp(-2ax²).
(3)
1. Explain in your own words what the terminology for each of the quantities in the
above expression is.
2. When k=n+m+p is an odd number, what can you say about the integral?
To perform these integrations we introduce the following integral and then employ integra-
tion by parts to develop a recursion relation:
etoo
I (2a) = |
) = [** dzz*ecxp(-2ax²)
(4)
1. If u = x2k-1 what is du?
2. If dv = xexp(-2ax²)dx, what is v?
3. What is the value of uv at x = 0? What is the value of uv at x = -oo?
4. What is the value of I-1(2a) in terms of I(2a)?
k I(2a)
|(m,p,n)
1
2
|(612*l61) = (øo]a*l60) = ($2\a²\&2) = (ø4|04)
TABLE I. Complete the table above by filling in the value of Ik(2a)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcb460c0c-d029-4e90-a450-1d82490780a1%2F0398f7b4-016c-4b38-a8b3-3233a82230c9%2F19zyha7_processed.jpeg&w=3840&q=75)
Transcribed Image Text:dro,(x)x® Óm(x) =| d
If we have trial functions, which depend on n, of the form ø,n = x"exp(-ax). We are
interested in being able to perform integrals (for any values of n, m and p) of the form:
+oo
dxr"+m+Pexp(-2ax²).
(3)
1. Explain in your own words what the terminology for each of the quantities in the
above expression is.
2. When k=n+m+p is an odd number, what can you say about the integral?
To perform these integrations we introduce the following integral and then employ integra-
tion by parts to develop a recursion relation:
etoo
I (2a) = |
) = [** dzz*ecxp(-2ax²)
(4)
1. If u = x2k-1 what is du?
2. If dv = xexp(-2ax²)dx, what is v?
3. What is the value of uv at x = 0? What is the value of uv at x = -oo?
4. What is the value of I-1(2a) in terms of I(2a)?
k I(2a)
|(m,p,n)
1
2
|(612*l61) = (øo]a*l60) = ($2\a²\&2) = (ø4|04)
TABLE I. Complete the table above by filling in the value of Ik(2a)
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)