The velocity of a ball changes from < 6, -6, 0 m/s to 5.92, -6.32, 0 m/s in 0.04 s, due to the gravitational attraction of the Earth and to air resistance. The mass of the ball is 140 grams. (a) What is the acceleration of the ball? (m/s)/s = X (b) What is the rate of change of momentum of the ball? dp/dt= (kg. m/s)/s (c) What is the net force acting on the ball? N net =
The velocity of a ball changes from < 6, -6, 0 m/s to 5.92, -6.32, 0 m/s in 0.04 s, due to the gravitational attraction of the Earth and to air resistance. The mass of the ball is 140 grams. (a) What is the acceleration of the ball? (m/s)/s = X (b) What is the rate of change of momentum of the ball? dp/dt= (kg. m/s)/s (c) What is the net force acting on the ball? N net =
University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter4: Motion In Two And Three Dimensions
Section: Chapter Questions
Problem 71P
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![The velocity of a ball changes from < 6, -6, 0 m/s to 5.92, -6.32, 0 m/s in 0.04 s, due to the gravitational attraction of the
Earth and to air resistance. The mass of the ball is 140 grams.
(a) What is the acceleration of the ball?
(m/s)/s
=
X
(b) What is the rate of change of momentum of the ball?
dp/dt=
(kg. m/s)/s
(c) What is the net force acting on the ball?
N
net
=](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6ec9c2f6-d9ab-41d9-a90f-248fb78d6daa%2F3427f08c-e9fa-4d91-aa65-5caa9504f237%2F9l3alyi_processed.png&w=3840&q=75)
Transcribed Image Text:The velocity of a ball changes from < 6, -6, 0 m/s to 5.92, -6.32, 0 m/s in 0.04 s, due to the gravitational attraction of the
Earth and to air resistance. The mass of the ball is 140 grams.
(a) What is the acceleration of the ball?
(m/s)/s
=
X
(b) What is the rate of change of momentum of the ball?
dp/dt=
(kg. m/s)/s
(c) What is the net force acting on the ball?
N
net
=
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