**Problem Statement:**A 2.91 kg particle has a velocity of \( (3.08 \, \mathbf{i} - 3.35 \, \mathbf{j}) \, \text{m/s} \).**Task:**(a) Find its x and y components of momentum.- \( p_x = 8.968 \) ❌ - *Feedback:* Your response is within 10% of the correct value. This may be due to round-off error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize round-off error. (Answer in \(\text{kg m/s}\))- \( p_y = -11.4945 \) ✔️ \(\, \text{kg m/s}\)(b) Find the magnitude and direction of its momentum.- Magnitude: \( 20.643 \) ❌ - *Feedback:* Your response differs from the correct answer by more than 10%. Double check your calculations. (Answer in \(\text{kg m/s}\))- Direction: \( 308.84^\circ \) ❌ (clockwise from the +x axis)---**Explanation:**In part (a), the components of momentum are calculated using the formula \( p = mv \), where \( m \) is mass and \( v \) is velocity. Each component should be calculated separately for the directions \( \mathbf{i} \) (x-axis) and \( \mathbf{j} \) (y-axis).In part (b), the magnitude of momentum is derived using the Pythagorean theorem on the components, and the direction uses the arctangent function to find the angle relative to the positive x-axis. Errors should be checked for precision and accuracy by ensuring all calculations use sufficient significant figures.

Given particle has mass M=2.91kg And its velocity is Therefore its momentum will be Here I've taken the value of momentum up two decimal places. Therefore we can see the x component of momentum is 8.96kg.m/s And y component of momentum is (-11.49kg.m/s)The magnitude of momentum each And its direction with x axis is This is the answer.

Answered: A 2.91 kg particle has a velocity of…