The vector position of a 3.85 g particle moving in the xy plane varies in time according to r1 = (3î + 3ĵ)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as r2 = 3î − 2ît2 − 6ĵt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.70 s. rcm =       cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.70 s. p =       g · cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.70 s. vcm =       cm/s

College Physics
11th Edition
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Chapter1: Units, Trigonometry. And Vectors
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The vector position of a 3.85 g particle moving in the xy plane varies in time according to
r1 = (3î + 3ĵ)t + 2ĵt2
where t is in seconds and
r
is in centimeters. At the same time, the vector position of a 5.35 g particle varies as
r2 = 3î − 2ît2 − 6ĵt.
(a)
Determine the vector position (in cm) of the center of mass of the system at t = 2.70 s.
rcm =
 
 
 
cm
(b)
Determine the linear momentum (in g · cm/s) of the system at t = 2.70 s.
p =
 
 
 
g · cm/s
(c)
Determine the velocity (in cm/s) of the center of mass at t = 2.70 s.
vcm =
 
 
 
cm/s
(d)
Determine the acceleration (in cm/s2) of the center of mass at t = 2.70 s.
acm =
 
 
 
cm/s2
(e)
Determine the net force (in µN) exerted on the two-particle system at t = 2.70 s.
Fnet =
 
 
 

µN

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