Mark (60 kg) and Jay (75 kg) are on an ice pond, with Mark's location at x = -15 m and Jay at x = +15 m. The location of their center of mass is solved as: XCM (60 kg)(-15 m) + (75 kg)(+15 m) 60 kg + 75 kg The center of mass is as XCM = 1.67 m. Mark and Jay now hold a massless rope between them. Mark pulls the rope, making her slide up to the position x = -5 m. Jay is also pulled toward Mark as a result. Where is the final location of Jay? (Provide full solution of the problem). Hint: There are no external forces acting on the system. Therefore, the location of the center of mass is preserved
Mark (60 kg) and Jay (75 kg) are on an ice pond, with Mark's location at x = -15 m and Jay at x = +15 m. The location of their center of mass is solved as: XCM (60 kg)(-15 m) + (75 kg)(+15 m) 60 kg + 75 kg The center of mass is as XCM = 1.67 m. Mark and Jay now hold a massless rope between them. Mark pulls the rope, making her slide up to the position x = -5 m. Jay is also pulled toward Mark as a result. Where is the final location of Jay? (Provide full solution of the problem). Hint: There are no external forces acting on the system. Therefore, the location of the center of mass is preserved
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![Mark (60 kg) and Jay (75 kg) are on an ice pond, with Mark's location at x = -15 m and Jay at
x = +15 m. The location of their center of mass is solved as:
XCM =
(60 kg)(-15 m) + (75 kg)(+15 m)
60 kg + 75 kg
The center of mass is as XCM = 1.67 m.
Mark and Jay now hold a massless rope between them. Mark pulls the rope, making
her slide up to the position x = -5 m. Jay is also pulled toward Mark as a result.
Where is the final location of Jay? (Provide full solution of the problem).
Hint:
There are no external forces acting on the system. Therefore, the location of the
center of mass is preserved.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe78f6592-8a12-4c12-9324-ecc147d18118%2F16a5a5aa-ed1a-488f-96d1-016e25c1ee8b%2Fny1unlb_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Mark (60 kg) and Jay (75 kg) are on an ice pond, with Mark's location at x = -15 m and Jay at
x = +15 m. The location of their center of mass is solved as:
XCM =
(60 kg)(-15 m) + (75 kg)(+15 m)
60 kg + 75 kg
The center of mass is as XCM = 1.67 m.
Mark and Jay now hold a massless rope between them. Mark pulls the rope, making
her slide up to the position x = -5 m. Jay is also pulled toward Mark as a result.
Where is the final location of Jay? (Provide full solution of the problem).
Hint:
There are no external forces acting on the system. Therefore, the location of the
center of mass is preserved.
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