The vector position of a 3.80 g particle moving in the xy plane varies in time according to r, = (31 + 3j)t + 2jt? where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as r, = 3î - 2ît? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.40 s. 4.744i – 7.38j cm 'cm (b) Determine the linear momentum (in g · cm/s) of the system at t = 2.40 s. p = 11.4i – 35.58j g. cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.40 s. = 1.245i – 3.888j cm/s cm (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.40 s. acm = 0.6775j cm/s² (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.40 s. Fnet = uN

College Physics
11th Edition
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Chapter1: Units, Trigonometry. And Vectors
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Enet =
The vector position of a 3.80 g particle moving in the xy plane varies in time according tor,
= (3î + 3j)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g
particle varies as
2
sr, = 3î – 2ît? - 6jt.
(a) Determine the vector position (in cm) of the center of mass of the system at t = 2.40 s.
rcm
4.744i – 7.38j
cm
(b) Determine the linear momentum (in g• cm/s) of the system at t = 2.40 s.
p =
11.4i – 35.58j
g• cm/s
(c) Determine the velocity (in cm/s) of the center of mass at t = 2.40 s.
1.245i – 3.888j
cm/s
=
cm
(d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.40 s.
0.6775j
cm/s?
=
cm
(e) Determine the net force (in µN) exerted on the two-particle system at t = 2.40 s.
µN
Transcribed Image Text:Enet = The vector position of a 3.80 g particle moving in the xy plane varies in time according tor, = (3î + 3j)t + 2ĵt2 where t is in seconds and r is in centimeters. At the same time, the vector position of a 5.35 g particle varies as 2 sr, = 3î – 2ît? - 6jt. (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.40 s. rcm 4.744i – 7.38j cm (b) Determine the linear momentum (in g• cm/s) of the system at t = 2.40 s. p = 11.4i – 35.58j g• cm/s (c) Determine the velocity (in cm/s) of the center of mass at t = 2.40 s. 1.245i – 3.888j cm/s = cm (d) Determine the acceleration (in cm/s2) of the center of mass at t = 2.40 s. 0.6775j cm/s? = cm (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.40 s. µN
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