A station wagon with mass mA = 1200 mB kg is moving along a straight highway at a speed va = 10 m/s. Another car, with mass mg = 1600 kg and speed vB = 15 m/s has its center of mass s = 60 m ahead of the center of mass of the station wagon. What is the speed of the center of mass of the system?
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- Three ice skaters meet at the center of a rink and each stands at rest facing the center, within arm's reach of the other two. On a signal, each skater pushes himself away from the other two across the frictionless ice. After the push, skater A with mass mA = 90.0 kg moves in the negative y-direction at 2.50 m/s and skater B with mass mB = 80.0 kg moves in the negative x-direction at 4.00 m/s. Find the x- and y-components of the 70.0 kg skater C's velocity (in m/s) after the push. HINT Vcx V CY = m/s m/sHomework Q9.Two blocks of masses mA = 7,9kg and mß = 19, 6kg, resting on a frictionless table, are connected to a strecthed (massless) spring and then released (from rest). The system consists of the two blocks and the spring and the net external force on the system is zero. What is the velocity of the center of mass once the system is released? ww MA VB mB
- The vector position of a 3.75 g particle moving in the xy plane varies in time according to r₁ = (3î + 3ĵ)t + 2ĵt² where t is in seconds and is in centimeters. At the same time, the vector position of a 5.65 g particle varies as r 31 – 2ît² – 6ĵt. r2 (a) Determine the vector position (in cm) of the center of mass of the system at t = 2.80 s. cm = (b) Determine the linear momentum (in g· cm/s) of the system at t = 2.80 s. cm cm (c) Determine the velocity (in cm/s) of the center of mass at t = 2.80 s. cm g.cm/s net (d) Determine the acceleration (in cm/s²) of the center of mass at t = 2.80 s. cm/s² = = cm/s (e) Determine the net force (in µN) exerted on the two-particle system at t = 2.80 s. μNThree solid, uniform boxes are aligned as in the figure below. Find the x- and y-coordinates (in m) of the center of mass of the three boxes, measured from the bottom left corner of box A. (Consider the three-box system.) HINT Xcm Y cm = Origin 0.300 m m m A 0.700 kg 0.350 m B 1.00 kg 0.150 m 0.450 kg L. 0.418 mA 1.82 kg particle has the xy coordinates (-1.78 m, 0.802 m), and a 4.12 kg particle has the xy coordinates (0.0660 m, -0.389 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 1.57 kg particle such that the center of mass of the three-particle system has the coordinates (-0.688 m, -0.956 m)?
- Object 1 is located at (-7,-4.6)m and has a mass of 49.5 kg. Object 2 is located at (1.5,5)m and has a mass of 64.1 kg. Object 3 is located at (-0.3,-6.5)m and has a mass of 34.7 kg. What is the x-coordinate of the center of mass of this three mass system?A particle with mass mA = 3.00 kg is located at rA = (2.50 i + 3.50 j) m, and a second particle of mass m2B = 5.00 kg is located at rB = (1.50 i – 3.00 j) m. Find the location of the center of mass of the system relative to the point (1,1).A 3 kg plank is 0.6 m in length and has its center of mass at the geometrical center. Masses of 1 kg an 3 kg are attached at opposite ends of the plank. Find the center of mass of the whole system. 1 kg 3 kg Where is the COM? 3 kg
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